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Re: Printer list value problem

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On 2014-01-14 19:24, Mike wrote:
> Hello,
> I confudsed,need printer the value of list (this is reaer from csv) . The reader is ok, but my problem is in the print moment because printer only the last value. For example my csv is:
>
> [........]
> user1@example.com;user1;lastName;Name
> user2@example.com;user2;lastName;Name
> [........]
>
> But when execute the script I view the print is only the last user
>
> [........]
> ca user2@example.com displayName 'user2' sn 'lastName' cn 'Name'
> [........]
>
> And I need the next printer
>
> [........]
> ca user1@example.com displayName 'User1' sn ''lastName" cn 'Name'
> ca user1@example.com displayName 'User2' sn ''lastName" cn 'Name'
> [........]
>
> My script is
>
> [........]
> #!/usr/bin/python
> import csv
> with open ('users.csv', 'rb') as f:
>
>          reader = csv.reader (f, delimiter=';' ) #delimiter tabulador
>          for row in reader:
>
>                  mail     = row [0]
>                  name     = row [3]
>                  lastname = row [2]
>

This line is indented the same amount as the 'for' loop, which means
that it will be executed after the loop has finished.

>          print "ma {} displayName '{}' sn '{}'".format(mail,name,lastname)
>
You don't need to close the file here because the 'with' statement will
do that for you.

> f.close()
> [........]
>
>
> Thanks.
>

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Printer list value problem Mike <miguelcoam@gmail.com> - 2014-01-14 11:24 -0800
  Re: Printer list value problem MRAB <python@mrabarnett.plus.com> - 2014-01-14 19:32 +0000
    Re: Printer list value problem Mike <miguelcoam@gmail.com> - 2014-01-14 11:54 -0800
      Re: Printer list value problem Mark Lawrence <breamoreboy@yahoo.co.uk> - 2014-01-14 20:03 +0000
  Re: Printer list value problem Tim Chase <python.list@tim.thechases.com> - 2014-01-14 13:38 -0600

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