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| To | "Clark\, Kathleen" <katie.clark@yale.edu> |
| From | Nick Dokos <nicholas.dokos@hp.com> |
| Subject | Re: TypeError |
| In-Reply-To | Message from "Clark\, Kathleen" <katie.clark@yale.edu> of "Wed\, 01 Feb 2012 16\:53\:41 GMT." <0610E9FC98B37742AD184612801101F834B04E@x10-mbx4.yu.yale.edu> |
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| Date | Wed, 01 Feb 2012 12:27:47 -0500 |
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Clark, Kathleen <katie.clark@yale.edu> wrote: > TypeError: sequence item 1: expected string, NoneType found > > The error message is referencing line 86 of my code: > > ws.cell(row=row, column=1).value = ','.join([str(ino), fn, ln, sdob]) > > If I’m understanding this correctly, the code is expecting a string, but not finding it. I’m > wondering, what is meant by a “string” and also how I can figure out the problem and correct it. I'd guess that the sequence in question is the list that's the argument of join(), in which case item 1 is fn: it should be a string but for some reason, it is a None value: ,---- | >>> ','.join([str(45), None, "bar", "foo"]) | Traceback (most recent call last): | File "<stdin>", line 1, in <module> | TypeError: sequence item 1: expected string, NoneType found |>>> ','.join([str(45), "a string", "bar", "foo"]) |'45,a string,bar,foo' `---- Nick
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Re: TypeError Nick Dokos <nicholas.dokos@hp.com> - 2012-02-01 12:27 -0500
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