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Re: Dictionary

References <x4jwu.3413$Bs5.1921@fx09.am4> <mailman.4725.1388433616.18130.python-list@python.org> <P6hzu.2028$Wn7.1602@fx20.am4> <vcprc9l33287s827e421tbib9tvlkb0pb1@4ax.com>
Date 2014-01-09 11:21 +1100
Subject Re: Dictionary
From Chris Angelico <rosuav@gmail.com>
Newsgroups comp.lang.python
Message-ID <mailman.5217.1389226906.18130.python-list@python.org> (permalink)

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On Thu, Jan 9, 2014 at 11:13 AM, Dennis Lee Bieber
<wlfraed@ix.netcom.com> wrote:
>         #generate search re expression representing
>         #       .*              any character/multiple -- leading
>         #       [l|e|t|t|e|r]   match any of the letters supplied
>         #       .*              any character/multiple -- trailing
>         needle = ".*[" + "|".join(list(letters.lower())) + "].*"

I don't think this will do what you think it will. It'll match
anything that has any one of the supplied letters (or a pipe; it's a
character class, so the pipe has no significance and is simply part of
the class). I'm not sure a regex is the best thing here; but what you
could do is sort the letters and sort the letters in the words:

pat = ".*".join(sorted(letters.lower()))
for word in open("/usr/share/dict/words"): # Ought to use with
    if re.search(pat, ''.join(sorted(word))): print(word)

ChrisA

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Thread

Dictionary Bischoop <martin@jakis.adres.em> - 2013-12-30 18:38 +0000
  Re: Dictionary Walter Hurry <walterhurry@gmail.com> - 2013-12-30 18:56 +0000
    Re: Dictionary Bischoop <martin@jakis.adres.em> - 2014-01-08 19:00 +0000
      Re: Dictionary wxjmfauth@gmail.com - 2014-01-09 00:31 -0800
  Re: Dictionary Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2013-12-30 15:00 -0500
    Re: Dictionary Bischoop <martin@jakis.adres.em> - 2014-01-08 18:51 +0000
      Re: Dictionary Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2014-01-08 19:13 -0500
      Re: Dictionary Chris Angelico <rosuav@gmail.com> - 2014-01-09 11:21 +1100

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