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| From | Terry Reedy <tjreedy@udel.edu> |
| Subject | Re: Division and multiplication have a different behavior in the overflow case |
| Date | Sat, 27 Jul 2013 16:56:48 -0400 |
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On 7/27/2013 1:48 PM, Marco wrote: > In Python 3, when we hava a division and both the result and at least > one operand are too large to convert to float, we get an exception: > > >>> 2**1028 / 2**-2 int/float gets converted to float/float and the int to float conversion is not possible. The result is irrelevant since it never gets calculated. > Traceback (most recent call last): > File "<input>", line 1, in <module> > OverflowError: long int too large to convert to float > > When the result is inside the limits, we get the right value: > > >>> 2 ** 1025 / 2**10 > 3.511119404027961e+305 This must be doing integer division and then converting the result to float, which it can. > Why the behavior is different in the case of the multiplication? > > >>> 2 ** 1025 * 2**-10 Mathematically this is the same thing, but computationally, it is not and you cannot expect to get the same answer. Like the first example, 2**-10 is a float, so 2**1025 must be converted to float to do float multiplication. But that is not possible. > Traceback (most recent call last): > File "<input>", line 1, in <module> > OverflowError: long int too large to convert to float > > I think the multiplication should have the same behavior than the > division: > > * `inf` or `-inf` when the operands are inside the limits, > but the result is not > * `OverflowError` when the result, and at least one operand, > are out of range. -- Terry Jan Reedy
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Division and multiplication have a different behavior in the overflow case Marco <m.b@gmail.com> - 2013-07-27 19:48 +0200 Re: Division and multiplication have a different behavior in the overflow case Terry Reedy <tjreedy@udel.edu> - 2013-07-27 16:56 -0400
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