Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > comp.lang.python > #19403

Re: Determining version of OpenSSL linked against python?

Show all headers | View raw

Hi

Is this possible at all?

Cheers

Adam

On Mon, Jan 23, 2012 at 14:01, Adam Mercer <ramercer@gmail.com> wrote:
> Hi
>
> I'm trying to write a script that determines the version of OpenSSL
> that python is linked against, using python-2.7 this is easy as I can
> use:
>
>    import ssl
>    ssl.OPENSSL_VERSION
>
> but unfortunately I need to support python-2.6, from an older script I
> used the following:
>
>    import _ssl
>    ssl_lib = _ssl.__file__
>
> to get the path to the _ssl.so module and then I parsed the output of
> ldd (on linux) to get the path to the OpenSSL library and then parsed
> the version from the filename. In other words it's very messy.
>
> I had a little success using this approach but I have recently
> received a bug report that this doesn't seem to work on Debian
> Squeeze. When I try to query the __file__ attribute of the _ssl module
> I get the following error:
>
>>>> import _ssl
>>>> _ssl.__file__
> Traceback (most recent call last):
>  File "<stdin>", line 1, in <module>
> AttributeError: 'module' object has no attribute '__file__'
>>>>
>
> Can anyone offer any suggestions as to what is going wrong with the
> above code or offer an alternative way of determining the OpenSSl
> version using python-2.6?
>
> Cheers
>
> Adam

Back to comp.lang.python | Previous | Next | Find similar | Unroll thread

Thread

Re: Determining version of OpenSSL linked against python? Adam Mercer <ramercer@gmail.com> - 2012-01-25 10:02 -0600

csiph-web