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| References | <51E6EEC3.50404@lavabit.com> |
|---|---|
| From | Ian Kelly <ian.g.kelly@gmail.com> |
| Date | 2013-07-17 14:10 -0600 |
| Subject | Re: Storing a very large number |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.4813.1374091886.3114.python-list@python.org> (permalink) |
On Wed, Jul 17, 2013 at 1:21 PM, Hasit Mistry <hasitnm@lavabit.com> wrote: > I came across a problem that requires me to store a very large number (say >>10^100). How do I do it efficiently? Both the int and Decimal types support arbitrary precision. Floats do not. > And also, how do I select a particular number (say 209th) from that very > large number? You mean a particular digit? The most obvious way is to format it as a string and use indexing. >>> x = 2 ** 1000 >>> str(x)[208] '6' Or using arithmetic: >>> (x // 10 ** 208) % 10 5 Note that the first method counts digits from the left and will be off if the value is negative, while the second method counts digits from the right.
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Re: Storing a very large number Ian Kelly <ian.g.kelly@gmail.com> - 2013-07-17 14:10 -0600
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