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Re: itertools py3.4 - filter list using not equal - fails as bool

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On 2015-05-12 23:43, Sayth Renshaw wrote:
> why can't I filter a list based on an itertools condition using dropwhile?
>
> This is the docs and the example. https://docs.python.org/3/library/itertools.html#itertools.dropwhile
>
> def less_than_10(x):
>      return x < 10
>
> itertools.takewhile(less_than_10, itertools.count()) =>
>    0, 1, 2, 3, 4, 5, 6, 7, 8, 9
>
> so I have a list I have created (converted from itertools). pm is permutations
>
>
> print(stats)
> [(1, 2, 3), (1, 2, 4), (1, 2, 5), (1, 3, 2), (1, 3, 4), (1, 3, 5), (1, 4, 2), (1, 4, 3), (1, 4, 5), (1, 5, 2), (1, 5, 3), (1, 5, 4), (2, 1, 3), (2, 1, 4), (2, 1, 5), (2, 3, 1), (2, 3, 4), (2, 3, 5), (2, 4, 1), (2, 4, 3), (2, 4, 5), (2, 5, 1), (2, 5, 3), (2, 5, 4), (3, 1, 2), (3, 1, 4), (3, 1, 5), (3, 2, 1), (3, 2, 4), (3, 2, 5), (3, 4, 1), (3, 4, 2), (3, 4, 5), (3, 5, 1), (3, 5, 2), (3, 5, 4), (4, 1, 2), (4, 1, 3), (4, 1, 5), (4, 2, 1), (4, 2, 3), (4, 2, 5), (4, 3, 1), (4, 3, 2), (4, 3, 5), (4, 5, 1), (4, 5, 2), (4, 5, 3), (5, 1, 2), (5, 1, 3), (5, 1, 4), (5, 2, 1), (5, 2, 3), (5, 2, 4), (5, 3, 1), (5, 3, 2), (5, 3, 4), (5, 4, 1), (5, 4, 2), (5, 4, 3)]
>
>
> I simply wanted to create an easy way to create summary stats of my stats list(poorly named). So in this case easy to check answers. so how many tuples in my list have a 1 in item[0] and how many don't. Then hoping to build on that for example how many have item[0] == 1 && (item[1] == 2 or item[1] == 4) etc.
>
> I can achieve it via an else if but that would become ugly quick.
>
> for item in stats:
>      if item[0] == 1:
>          nums += 1
>      elif item[0] != 1:
>          not_in += 1
>      else:
>          pass
>
>
> myString = "i have {a} in and {b} so the percentage is {c}%".format(a=nums, b=not_in, c=(nums/(nums + not_in)))
>
> I thought dropwhile from the docs appeared a good option but it returns bool.
>
> answer = listb.extend(itertools.dropwhile(item[0] != 1, stats))
> ---------------------------------------------------------------------------
> TypeError                                 Traceback (most recent call last)
> <ipython-input-130-70c93104d1c5> in <module>()
> ----> 1 answer = listb.extend(itertools.dropwhile(item[0] != 1, stats))
>
> TypeError: 'bool' object is not callable
>
That evaluates:

     item[0] != 1

which returns True or False. Apparently, "item" happens to be bound to
something that can be subscripted.

It then calls:

     itertools.dropwhile(..., stats)

passing the bool as the first argument (the predicate) of dropwhile.

When it tries to test the first item from stats, it discovers that the
predicate is not callable; it's a bool.

Result: TypeError!

And another point: a list's "extend" method modifies the list and then
returns None, so "answer" will be None.

> Think I am making this hard somewhere that it is actually easy.
>
> As an aside do I really need to convert the iterator object to a list to create and summarize iterator contents?
>
> Currently I have created a function to achieve this as below.
>
> def myGen(parcel):
>      x = []

Don't use a list comprehension like this:

>      [x.append(y) for y in parcel]

Do this instead:

     for y in parcel:
         x.append(y)

or, alternatively, this:

     x.extend(parcel)

>      return x
>
> myPerm = pm(range(1,6),3)
>
> stats = myGen(myPerm)
>

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Thread

itertools py3.4 - filter list using not equal - fails as bool Sayth Renshaw <flebber.crue@gmail.com> - 2015-05-12 15:43 -0700
  Re: itertools py3.4 - filter list using not equal - fails as bool MRAB <python@mrabarnett.plus.com> - 2015-05-13 00:22 +0100
  Re: itertools py3.4 - filter list using not equal - fails as bool Peter Otten <__peter__@web.de> - 2015-05-13 09:40 +0200
    Re: itertools py3.4 - filter list using not equal - fails as bool Sayth Renshaw <flebber.crue@gmail.com> - 2015-05-13 06:58 -0700

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