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timedelta and float multiplication in python 2

From Nagy László Zsolt <gandalf@shopzeus.com>
Newsgroups comp.lang.python
Subject timedelta and float multiplication in python 2
Date 2016-02-11 11:39 +0100
Message-ID <mailman.42.1455187570.22075.python-list@python.org> (permalink)

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I ran into a problem today where I had to determine the mean point
between two datetimes. Here is an example:

>>> start = datetime.datetime(2016,2,11)
>>> stop = datetime.datetime.now()
>>> mean = start + (stop-start)*0.5
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
TypeError: unsupported operand type(s) for *: 'datetime.timedelta' and
'float'

A workaround could be something like this:

>>> start + datetime.timedelta(seconds=0.5*((stop-start).total_seconds()))
datetime.datetime(2016, 2, 11, 5, 45, 45, 818009)

Interesting thing is that total_seconds() already returns fractions of
seconds, so it would be almost trivial to implement timedelta
multiplication with floats.

I have checked and it does work with Python 3. But it does not work with
Python 2 - is there a good reason for this?

Thanks,

   Laszlo

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timedelta and float multiplication in python 2 Nagy László Zsolt <gandalf@shopzeus.com> - 2016-02-11 11:39 +0100

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