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| References | <5CB71036-C359-4211-8B3B-62B17AACF88E@gmail.com> |
|---|---|
| From | Ian Kelly <ian.g.kelly@gmail.com> |
| Date | 2013-07-31 11:07 -0600 |
| Subject | Re: Lambda function Turing completeness |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.40.1375290509.1251.python-list@python.org> (permalink) |
On Wed, Jul 31, 2013 at 12:53 AM, Musical Notation <musicdenotation@gmail.com> wrote: > Is it possible to write a Turing-complete lambda function (which does not depend on named functions) in Python? Yes, lambda functions are Turing-complete. You can get anonymous recursion by defining the function to take a recursive function argument and then passing it to itself. For example, this will (inefficiently) give you the 13th Fibonacci number: (lambda f, n: f(f, n))(lambda f, n: n if n < 2 else f(f, n-2) + f(f, n-1), 13)
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Re: Lambda function Turing completeness Ian Kelly <ian.g.kelly@gmail.com> - 2013-07-31 11:07 -0600
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