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Re: list comprehension misbehaving

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Wolfgang Maier wrote:

> Dear all, with
> a=list(range(1,11))
> 
> why (in Python 2.7 and 3.3) is this explicit for loop working:
> for i in a[:-1]:
>     a.pop() and a
> 
> giving:
> [1, 2, 3, 4, 5, 6, 7, 8, 9]
> [1, 2, 3, 4, 5, 6, 7, 8]
> [1, 2, 3, 4, 5, 6, 7]
> [1, 2, 3, 4, 5, 6]
> [1, 2, 3, 4, 5]
> [1, 2, 3, 4]
> [1, 2, 3]
> [1, 2]
> [1]

No. Introduce a result list, and you'll see that you append the *same* list 
to the result nine times:

>>> a = range(1, 11)
>>> result = []
>>> for i in a[:-1]:
...     result.append(a.pop() and a)
... 
>>> result
[[1], [1], [1], [1], [1], [1], [1], [1], [1]]

> but the equivalent comprehension failing:
> [a.pop() and a for i in a[:-1]]
> 
> giving:
> [[1], [1], [1], [1], [1], [1], [1], [1], [1]]
> 
> ???
> Especially, since these two things *do* work as expected:
> [a.pop() and a[:] for i in a[:-1]]
> [a.pop() and print(a) for i in a[:-1]] # Python 3 only

So you already know the solution to your problem...

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Re: list comprehension misbehaving Peter Otten <__peter__@web.de> - 2013-03-28 16:48 +0100

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