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Groups > comp.lang.python > #17626
| Date | 2011-12-21 01:01 +0100 |
|---|---|
| From | Alexander Kapps <alex.kapps@web.de> |
| Subject | Re: Text Processing |
| References | <209c2abf-dd56-4a7f-839b-fad92920d457@m7g2000vbc.googlegroups.com> <20111220210321.77451e19@bouzin.lan> <7895.1324415085@alphaville.americas.hpqcorp.net> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.3887.1324425704.27778.python-list@python.org> (permalink) |
On 20.12.2011 22:04, Nick Dokos wrote:
>>> I have a text file containing such data ;
>>>
>>> A B C
>>> -------------------------------------------------------
>>> -2.0100e-01 8.000e-02 8.000e-05
>>> -2.0000e-01 0.000e+00 4.800e-04
>>> -1.9900e-01 4.000e-02 1.600e-04
>>>
>>> But I only need Section B, and I need to change the notation to ;
>>>
>>> 8.000e-02 = 0.08
>>> 0.000e+00 = 0.00
>>> 4.000e-02 = 0.04
> Does it have to be python? If not, I'd go with something similar to
>
> sed 1,2d foo.data | awk '{printf("%.2f\n", $2);}'
>
Why sed and awk:
awk 'NR>2 {printf("%.2f\n", $2);}' data.txt
And in Python:
f = open("data.txt")
f.readline() # skip header
f.readline() # skip header
for line in f:
print "%02s" % float(line.split()[1])
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Text Processing Yigit Turgut <y.turgut@gmail.com> - 2011-12-20 11:17 -0800
Re: Text Processing Dave Angel <d@davea.name> - 2011-12-20 14:57 -0500
Re: Text Processing Jérôme <jerome@jolimont.fr> - 2011-12-20 21:03 +0100
Re: Text Processing Nick Dokos <nicholas.dokos@hp.com> - 2011-12-20 16:04 -0500
Re: Text Processing Alexander Kapps <alex.kapps@web.de> - 2011-12-21 01:01 +0100
Re: Text Processing Yigit Turgut <y.turgut@gmail.com> - 2011-12-22 03:11 -0800
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