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| References | <l84aor$3mj$1@news.albasani.net> <CAPM-O+z4vuhoyKuEVdoYxJe42qhXT89GQTyQEHGjvm+c8yV3NQ@mail.gmail.com> <CAPM-O+yssdgztsRZjZOWE8k8OaB_2sg3nnd1zQM=osZ0ggE0ow@mail.gmail.com> <CAPTjJmoz1A2ASai3sZFXdJ9jaYDV-BGPgfdgGGTz-b4e3uuqKQ@mail.gmail.com> |
|---|---|
| Date | 2013-12-10 19:50 +1100 |
| Subject | Re: Programming puzzle with boolean circuits |
| From | Chris Angelico <rosuav@gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.3815.1386665450.18130.python-list@python.org> (permalink) |
On Tue, Dec 10, 2013 at 1:21 PM, Chris Angelico <rosuav@gmail.com> wrote: > Output: (I tweaked my __repr__ functions to parenthesize for clarity) > > (((not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and not ((($1 and > $2) and $4) or (not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and > (($1 or $2) or $4)))) or ((not ((($1 and $2) or ($1 and $4)) or ($2 > and $4)) and (($1 or $2) or $4)) and ($2 or $4))) or ((not ((($1 and > $2) and $4) or (not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and > (($1 or $2) or $4))) and ((($1 and $2) or ($1 and $4)) or ($2 and > $4))) and ($2 and $4))) > (((not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and not ((($1 and > $2) and $4) or (not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and > (($1 or $2) or $4)))) or ((not ((($1 and $2) or ($1 and $4)) or ($2 > and $4)) and (($1 or $2) or $4)) and ($1 or $4))) or ((not ((($1 and > $2) and $4) or (not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and > (($1 or $2) or $4))) and ((($1 and $2) or ($1 and $4)) or ($2 and > $4))) and ($1 and $4))) > (((not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and not ((($1 and > $2) and $4) or (not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and > (($1 or $2) or $4)))) or ((not ((($1 and $2) or ($1 and $4)) or ($2 > and $4)) and (($1 or $2) or $4)) and ($2 or $1))) or ((not ((($1 and > $2) and $4) or (not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and > (($1 or $2) or $4))) and ((($1 and $2) or ($1 and $4)) or ($2 and > $4))) and ($2 and $1))) > > Okay, so maybe the brute-force-discovered version isn't so bad after all. :) I added the same parenthesizing to the brute force searcher and reran it through 'time'. ~$1 = (($4 or not (($1 and $2) or ($4 and ($1 or $2)))) and (($4 and not (($1 and $2) or ($4 and ($1 or $2)))) or (($2 or not (($1 and $2) or ($4 and ($1 or $2)))) and (($2 and not (($1 and $2) or ($4 and ($1 or $2)))) or not (($2 or ($1 or $4)) and (($2 and ($1 and $4)) or not (($1 and $2) or ($4 and ($1 or $2))))))))) ~$2 = (($4 or not (($1 and $2) or ($4 and ($1 or $2)))) and (($4 and not (($1 and $2) or ($4 and ($1 or $2)))) or (($1 or not (($1 and $2) or ($4 and ($1 or $2)))) and (($1 and not (($1 and $2) or ($4 and ($1 or $2)))) or not (($2 or ($1 or $4)) and (($2 and ($1 and $4)) or not (($1 and $2) or ($4 and ($1 or $2))))))))) ~$4 = (($2 or not (($1 and $2) or ($4 and ($1 or $2)))) and (($2 and not (($1 and $2) or ($4 and ($1 or $2)))) or (($1 or not (($1 and $2) or ($4 and ($1 or $2)))) and (($1 and not (($1 and $2) or ($4 and ($1 or $2)))) or not (($2 or ($1 or $4)) and (($2 and ($1 and $4)) or not (($1 and $2) or ($4 and ($1 or $2))))))))) real 362m12.261s user 362m7.186s sys 0m0.064s Yes, that is indeed six full hours of CPU time for a simple problem. Ha! It seems to have come up with something fairly similar, actually. A bit shorter than the algebraic solution. brute: (($4 or not (($1 and $2) or ($4 and ($1 or $2)))) and (($4 and not (($1 and $2) or ($4 and ($1 or $2)))) or (($2 or not (($1 and $2) or ($4 and ($1 or $2)))) and (($2 and not (($1 and $2) or ($4 and ($1 or $2)))) or not (($2 or ($1 or $4)) and (($2 and ($1 and $4)) or not (($1 and $2) or ($4 and ($1 or $2))))))))) algebra: (((not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and not ((($1 and $2) and $4) or (not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and (($1 or $2) or $4)))) or ((not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and (($1 or $2) or $4)) and ($2 or $4))) or ((not ((($1 and $2) and $4) or (not ((($1 and $2) or ($1 and $4)) or ($2 and $4)) and (($1 or $2) or $4))) and ((($1 and $2) or ($1 and $4)) or ($2 and $4))) and ($2 and $4))) Here's the most notable difference: two_or_three = (a & b) | (a & c) | (b & c) can be simplified to: two_or_three = (a & b) | (c & (a | b)) That's one less gate in an early step. Even applying that change, though, the brute-forced solution is still a bit shorter. Looks like the algebraic solution could have a bit of optimization done! ChrisA
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Programming puzzle with boolean circuits Johannes Bauer <dfnsonfsduifb@gmx.de> - 2013-12-09 12:49 +0100
Re: Programming puzzle with boolean circuits Chris Angelico <rosuav@gmail.com> - 2013-12-10 00:25 +1100
Re: Programming puzzle with boolean circuits Johannes Bauer <dfnsonfsduifb@gmx.de> - 2013-12-11 14:52 +0100
Re: Programming puzzle with boolean circuits Joel Goldstick <joel.goldstick@gmail.com> - 2013-12-09 15:19 -0500
Spoiler alert? (Re: Programming puzzle with boolean circuits) John Ladasky <john_ladasky@sbcglobal.net> - 2013-12-09 12:39 -0800
Re: Spoiler alert? (Re: Programming puzzle with boolean circuits) Joel Goldstick <joel.goldstick@gmail.com> - 2013-12-09 15:45 -0500
Re: Programming puzzle with boolean circuits Chris Angelico <rosuav@gmail.com> - 2013-12-10 12:41 +1100
Fwd: Programming puzzle with boolean circuits Joel Goldstick <joel.goldstick@gmail.com> - 2013-12-09 21:03 -0500
Re: Programming puzzle with boolean circuits Chris Angelico <rosuav@gmail.com> - 2013-12-10 13:21 +1100
Re: Programming puzzle with boolean circuits Chris Angelico <rosuav@gmail.com> - 2013-12-10 19:50 +1100
Re: Programming puzzle with boolean circuits Antoon Pardon <antoon.pardon@rece.vub.ac.be> - 2013-12-10 15:25 +0100
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