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Re: Jython callable. How?

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> Perhaps if you show us what you actually do, and what happens, we might
> be able to tell you what is happening. Please COPY AND PASTE the full
> traceback.

Here is my code:
# Trying to make callable staticmethod

class sm(staticmethod):

   def __call__(self, *args, **kwargs):
       """ I know here is one more potential problem, because object
passed instead of real class """
       return self.__get__(None, object)(*args, **kwargs)

issubclass(sm, Callable)

class Foo(object):

   @sm
   def bar():
       print("ololo")

   print("inside", bar, callable(bar), bar())

if __name__=="__main__":
   print("class outise", Foo.bar, callable(Foo.bar), Foo.bar())
   f = Foo()
   print("instance outside", f.bar, callable(f.bar), f.bar())


cpython output:
ololo
('inside', <__main__.sm object at 0xb72b404c>, True, None)
ololo
('class outise', <function bar at 0xb72a680c>, True, None)
ololo
('instance outside', <function bar at 0xb72a680c>, True, None)

jython output:
Traceback (most recent call last):
 File "sm.py", line 17, in <module>
   class Foo(object):
 File "sm.py", line 23, in Foo
   print("inside", bar, callable(bar), bar())
TypeError: 'staticmethod' object is not callable

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Jython callable. How? Sirotin Roman <web.elektro.net@gmail.com> - 2012-03-04 16:03 +0700
  Re: Jython callable. How? Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2012-03-04 10:26 +0000
    Re: Jython callable. How? Sirotin Roman <web.elektro.net@gmail.com> - 2012-03-04 21:14 +0700

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