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| Date | Tue, 31 Mar 2015 16:50:12 +0200 |
| From | Ervin Hegedüs <airween@gmail.com> |
| To | python-list@python.org |
| Subject | Lockfile hanling |
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Hello,
there is an app, written in Python, which stores few bytes of
datas in a single file. The application uses threads. Every
thread can modify the file, but only one at a time. I'm using a
lock file to prevent the multiple access.
Here is the lock method:
while True:
try:
fl = os.open(self.lockfile, os.O_CREAT | os.O_EXCL | os.O_RDWR)
except OSError, e:
if e.errno != errno.EEXIST:
raise
time.sleep(0.2)
continue
except:
syslog.syslog(syslog.LOG_DEBUG, "Sync error: " + str(sys.exc_info()[1]))
else:
break
This works as well for me - about 3-4 weeks. After some weeks, I
got this error:
OSError: [Errno 24] Too many open files: '/var/spool/myapp/queue.lock'
Today the app had been restarted, about 3-4 hours ago. Now I see
under the proc/PID/fd:
lrwx------ 1 root root 64 márc 31 16.45 5 -> /var/spool/myapp/queue.lock (deleted)
there are about 50 deleted FD's. After few weeks the process
reaches the number if max fd's.
How can I prevent or avoid this issue? What's the correct way to
handle the lockfile in Python?
Thanks,
Ervin
Back to comp.lang.python | Previous | Next — Next in thread | Find similar | Unroll thread
Lockfile hanling Ervin Hegedüs <airween@gmail.com> - 2015-03-31 16:50 +0200
Re: Lockfile hanling Christian Gollwitzer <auriocus@gmx.de> - 2015-03-31 20:58 +0200
Re: Lockfile hanling Ian Kelly <ian.g.kelly@gmail.com> - 2015-03-31 13:17 -0600
Re: Lockfile hanling Christian Gollwitzer <auriocus@gmx.de> - 2015-03-31 21:59 +0200
Re: Lockfile hanling Ian Kelly <ian.g.kelly@gmail.com> - 2015-03-31 14:12 -0600
Re: Lockfile hanling Sturla Molden <sturla.molden@gmail.com> - 2015-04-01 23:51 +0000
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