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Groups > comp.lang.python > #21181
| References | <4obb29-os3.ln1@archaeopteryx.softver.org.mk> <CAMZYqRS=kSo7LG5i26E0qgfXxovKvjBy4XiTEpquw4H1OVV2dg@mail.gmail.com> |
|---|---|
| Date | 2012-03-03 21:57 -0800 |
| Subject | Re: The original command python line |
| From | Chris Rebert <clp2@rebertia.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.370.1330840664.3037.python-list@python.org> (permalink) |
On Sat, Mar 3, 2012 at 9:48 PM, Chris Rebert <clp2@rebertia.com> wrote: > On Sat, Mar 3, 2012 at 9:38 PM, Damjan Georgievski <gdamjan@gmail.com> wrote: >> How can I get the *really* original command line that started my python >> interpreter? <snip> > On Linux, you can read from: > /proc/<PID here>/cmdline > to get the null-delimited "command line". After some further searching: psutil offers `Process.cmdline` cross-platform; see http://code.google.com/p/psutil/wiki/Documentation Cheers, Chris
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The original command python line Damjan Georgievski <gdamjan@gmail.com> - 2012-03-04 06:38 +0100
Re: The original python command line Damjan Georgievski <gdamjan@gmail.com> - 2012-03-04 06:52 +0100
Re: The original command python line Chris Rebert <clp2@rebertia.com> - 2012-03-03 21:48 -0800
Re: The original command python line Grant Edwards <invalid@invalid.invalid> - 2012-03-04 14:34 +0000
Re: The original command python line Chris Rebert <clp2@rebertia.com> - 2012-03-03 21:57 -0800
Re: The original command python line Damjan Georgievski <gdamjan@gmail.com> - 2012-03-04 07:20 +0100
Re: The original command python line Devin Jeanpierre <jeanpierreda@gmail.com> - 2012-03-04 02:19 -0500
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