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RE: How to automatically get the indent level from code?

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I realize this isn't yet precisely what you're asking for, but look at the inspect and ast modules:

    import ast, inspect

    def indent_level():
        lineno = inspect.currentframe().f_back.f_lineno

        with open(__file__) as source_file:
            tree = ast.parse(source_file.read(), filename=__file__)

        for node in ast.walk(tree):
            if hasattr(node, 'lineno') and node.lineno == lineno:
                return node.col_offset

    def example_usage():
        print("first indent_level() = {0}".format(indent_level()))
        if True:
            print("second indent_level() = {0}".format(indent_level()))

    if __name__ == '__main__':
        example_usage()

The indent_level function above returns the textual column offset rather than the logical block level you're asking for, e.g.:

    first indent_level() = 4
    second indent_level() = 8

But hopefully it's a start.

Mark

-----Original Message-----
From: Python-list [mailto:python-list-bounces+mshroyer=awaredigital.com@python.org] On Behalf Of Peng Yu
Sent: Sunday, March 17, 2013 12:53 AM
To: python-list@python.org
Subject: How to automatically get the indent level from code?

Hi,

I want to get the indent level within the code. For example, I want to
print 1 within the while loop as the line is indented 1 level. Is it
possible to get it within python?

while 1:
   #print the level of indent, which is 1 here.

-- 
Regards,
Peng
-- 
http://mail.python.org/mailman/listinfo/python-list

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RE: How to automatically get the indent level from code? Mark Shroyer <mshroyer@awaredigital.com> - 2013-03-17 02:23 -0400

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