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Groups > comp.lang.python > #87378
| Date | 2015-03-13 17:29 +0000 |
|---|---|
| From | MRAB <python@mrabarnett.plus.com> |
| Subject | Re: regex help |
| References | <CACwCsY6cN6+mZVYWnMpKGsXg6jd7Y8Gav9DC7HkXcPtU-pDXDw@mail.gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.333.1426267966.21433.python-list@python.org> (permalink) |
On 2015-03-13 16:05, Larry Martell wrote: > I need to remove all trailing zeros to the right of the decimal point, > but leave one zero if it's whole number. For example, if I have this: > > 14S,5.0000000000000000,4.56862745000000,3.7272727272727271,3.3947368421052630,5.7307692307692308,5.7547169811320753,4.9423076923076925,5.7884615384615383,5.137254901960000 > > I want to end up with: > > 14S,5.0,4.56862745,3.7272727272727271,3.394736842105263,5.7307692307692308,5.7547169811320753,4.9423076923076925,5.7884615384615383,5.13725490196 > > I have a regex to remove the zeros: > > '0+[,$]', '' > > But I can't figure out how to get the 5.0000000000000000 to be 5.0. > I've been messing with the negative lookbehind, but I haven't found > one that works for this. > Search: (\.\d+?)0+\b Replace: \1 which is: re.sub(r'(\.\d+?)0+\b', r'\1', string)
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Re: regex help MRAB <python@mrabarnett.plus.com> - 2015-03-13 17:29 +0000
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