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| Date | Fri, 2 Nov 2012 20:11:49 +1100 |
| Subject | Re: pythonic way |
| From | Chris Angelico <rosuav@gmail.com> |
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On Fri, Nov 2, 2012 at 7:58 PM, jack <naruto0.1@live.cn> wrote:
> thanks,but I don't think enumerate() is my want
> Have some ways to operate the reference of element,not a copy when I tried
> to traverse a list?
>
> I'm so sorry about my poor English, hope you don't mind it.
No probs, I'll be a little less vague and pointer-y and give you some
example code. :)
lst = ['foo', 'bar', 'quux', 'asdf', 'qwer', 'zxcv']
for idx, val in enumerate(lst):
if val[1]=='w': lst[idx]='Replaced'
print(lst)
['foo', 'bar', 'quux', 'asdf', 'Replaced', 'zxcv']
Does that explain it a bit better? You get the index and can then
mutate the list using that index, thus replacing the original entry.
ChrisA
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Re: pythonic way Chris Angelico <rosuav@gmail.com> - 2012-11-02 20:11 +1100
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