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Groups > comp.lang.python > #101503
| From | Terry Reedy <tjreedy@udel.edu> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | Re: I'm missing something here... |
| Date | 2016-01-11 19:36 -0500 |
| Message-ID | <mailman.31.1452559005.13488.python-list@python.org> (permalink) |
| References | <CANc-5Uw6M7p9bLXhpET=6wdQz=vA-veDps_L-Q98utzYcs9+sg@mail.gmail.com> |
On 1/11/2016 6:26 PM, Skip Montanaro wrote:
> Here's a dumb little bit of code, adapted from a slightly larger script:
>
> #!/usr/bin/env python
>
> "dummy"
>
> import glob
> import os
>
> def compare_prices(*_args):
> "dummy"
> return set()
>
> def find_problems(cx1, cx2, cx3, prob_dates):
> "dummy"
> for fff in sorted(glob.glob("/path/to/*.nrm")):
> sym = os.path.splitext(os.path.basename(fff))[0]
> prob_dates |= compare_prices("E:%s"%sym, cx1, cx2, cx3)
>
> When I run pylint against it, it complains:
>
> junk.py:10: [W0613(unused-argument), find_problems] Unused argument 'prob_dates'
>
> I must be misunderstanding something about the |= operator as applied
> to sets. If I read the docs correctly, s1 |= s2 is equivalent to
> s1.update(s2). A dumb "test" at the prompt suggests that's true:
>
>>>> s1 = set("abc")
>>>> s2 = set("cde")
>>>> s1 | s2
> set(['a', 'c', 'b', 'e', 'd'])
>>>> s1 |= s2
>>>> s1
> set(['a', 'c', 'b', 'e', 'd'])
>>>> s1 = set("abc")
>>>> s1.update(s2)
>>>> s1
> set(['a', 'c', 'b', 'e', 'd'])
>
> If I change the last line of find_problems to call
> prob_dates.update(), the message disappears. Why is pylint (1.4.2 BTW)
> complaining that the prob_dates argument of find_problems is unused
> when I use the |= operator?
A bug in pylint. It should treat both cases the same.
--
Terry Jan Reedy
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Re: I'm missing something here... Terry Reedy <tjreedy@udel.edu> - 2016-01-11 19:36 -0500
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