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Groups > comp.lang.python > #40896
| Date | 2013-03-08 14:28 -0600 |
|---|---|
| Subject | itertools doc example "consume" |
| From | Skip Montanaro <skip@pobox.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.3097.1362774511.2939.python-list@python.org> (permalink) |
I've never really used itertools before. While trying to figure out
how to break a list up into equal pieces, I came across the consume
function in the examples here:
http://docs.python.org/2/library/itertools.html
It seems to me that it should return whatever it consumes from the
list. I thought you would call it like this:
for chunk in consume(range(30), 5):
print chunk
and see it print something like
[0, 1, 2, 3, 4]
[5, 6, 7, 8, 9]
...
[25, 26, 27, 28, 29]
If I call it like this:
lst = range(30)
consume(lst, 5)
it doesn't actually consume anything from lst. Am I missing
something, or is that example missing a return or yield statement?
Thanks,
Skip
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itertools doc example "consume" Skip Montanaro <skip@pobox.com> - 2013-03-08 14:28 -0600
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