Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.lang.python > #40539
| Path | csiph.com!usenet.pasdenom.info!gegeweb.org!de-l.enfer-du-nord.net!feeder1.enfer-du-nord.net!newsfeed.eweka.nl!feeder3.eweka.nl!81.171.88.16.MISMATCH!eweka.nl!hq-usenetpeers.eweka.nl!xlned.com!feeder5.xlned.com!news2.euro.net!newsgate.cistron.nl!newsgate.news.xs4all.nl!post.news.xs4all.nl!not-for-mail |
|---|---|
| Return-Path | <davea@davea.name> |
| X-Original-To | python-list@python.org |
| Delivered-To | python-list@mail.python.org |
| X-Spam-Status | OK 0.011 |
| X-Spam-Evidence | '*H*': 0.98; '*S*': 0.00; 'example:': 0.03; 'calculates': 0.09; 'terminate.': 0.09; 'termination': 0.09; 'def': 0.10; 'stack': 0.15; 'iteration': 0.16; 'iteration.': 0.16; 'itertools': 0.16; 'loops': 0.16; 'lot!': 0.16; 'simplified': 0.16; 'still,': 0.16; 'temp': 0.16; 'wrote:': 0.17; '(or': 0.18; 'otherwise,': 0.20; 'parameters': 0.20; 'import': 0.21; 'runs': 0.22; 'for?': 0.23; 'script': 0.24; 'specifically': 0.24; 'header :In-Reply-To:1': 0.25; 'header:User-Agent:1': 0.26; 'am,': 0.27; 'implies': 0.29; 'way?': 0.29; 'case,': 0.29; 'print': 0.32; 'problem': 0.33; 'to:addr:python-list': 0.33; 'thanks': 0.34; 'but': 0.36; 'too': 0.36; 'uses': 0.37; 'far': 0.37; 'subject:: ': 0.38; 'to:addr:python.org': 0.39; 'received:192': 0.39; 'received:192.168': 0.40; 'your': 0.60; 'more': 0.63; 'hello!': 0.65; 'received:74.208': 0.71; '10:32': 0.84; 'recursion,': 0.84; 'room).': 0.84; 'temperature': 0.84; 'temperature,': 0.84; 'ana': 0.91 |
| Date | Tue, 05 Mar 2013 11:02:03 -0500 |
| From | Dave Angel <davea@davea.name> |
| User-Agent | Mozilla/5.0 (X11; Linux x86_64; rv:17.0) Gecko/20130106 Thunderbird/17.0.2 |
| MIME-Version | 1.0 |
| To | python-list@python.org |
| Subject | Re: Recursive function |
| References | <9ff73ed4-24cd-4a61-bb54-a67dd4a96ed0@r9g2000vbh.googlegroups.com> |
| In-Reply-To | <9ff73ed4-24cd-4a61-bb54-a67dd4a96ed0@r9g2000vbh.googlegroups.com> |
| Content-Type | text/plain; charset=ISO-8859-1; format=flowed |
| Content-Transfer-Encoding | 8bit |
| X-Provags-ID | V02:K0:lcR0Bjk3HLs47MlI6IHA/nag4z+HCBvIie8E29YeGtt MGaXlkYjfgBGZ6I8rRTJJwht3DNNvF22+5XudwWnQAZn0N+sZC 1ZAJotVRIOR7lsmPjC/HpZD+z5wY68pwrCA3CV/9TmEiM6naXi ehkCDiqX0i6lptkbi+kuYanNUrfIAw+4SAHM97XGCPNTgYwL8X MJojBbaX8mwDct8tlr8YSAt+QCn1tylFQqF6jeDSqNtn8Ahujx x42YPGxwkYOsE7NtmcTChWVA0AOAxwf2/4it5caHZFnxnpG+7W SCVOsnvMZx2GQWhWh0FyVEJNE0mh1VH3mWc4p97u7YwKbzapw= = |
| X-BeenThere | python-list@python.org |
| X-Mailman-Version | 2.1.15 |
| Precedence | list |
| List-Id | General discussion list for the Python programming language <python-list.python.org> |
| List-Unsubscribe | <http://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe> |
| List-Archive | <http://mail.python.org/pipermail/python-list/> |
| List-Post | <mailto:python-list@python.org> |
| List-Help | <mailto:python-list-request@python.org?subject=help> |
| List-Subscribe | <http://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.2891.1362499338.2939.python-list@python.org> (permalink) |
| Lines | 51 |
| NNTP-Posting-Host | 2001:888:2000:d::a6 |
| X-Trace | 1362499338 news.xs4all.nl 6967 [2001:888:2000:d::a6]:57411 |
| X-Complaints-To | abuse@xs4all.nl |
| Xref | csiph.com comp.lang.python:40539 |
Show key headers only | View raw
On 03/05/2013 10:32 AM, Ana Dionísio wrote:
> Hello!
>
> I have to make a script that calculates temperature, but one of the
> parameters is the temperature in the iteration before, for example:
> temp = (temp_-1)+1
>
> it = 0
> temp = 3
>
> it = 1
> temp = 3+1
>
> it = 2
> temp = 4+1
>
> How can I do this in a simple way?
>
> Thanks a lot!
>
Recursion only works when you have a termination condition. Otherwise,
it just loops endlessly (or more specifically until the stack runs out
of room). Still, you don't have a problem that even implies recursion,
just iteration.
For your simple case, there's a simple formula:
def find_temp(it):
return it+3
Methinks you have simplified the problem too far to make any sense.
import itertools
temp = 3
for it in itertools.count():
temp += 1
print it, temp
Warning: that loop will never terminate.
Is this what you were looking for? It uses recursion, and I used <=0
for the termination condition.
def find_temp2(it):
if it <=0: return 3
return find_temp(it-1)
--
DaveA
Back to comp.lang.python | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread
Recursive function Ana Dionísio <anadionisio257@gmail.com> - 2013-03-05 07:32 -0800
Re: Recursive function Dave Angel <davea@davea.name> - 2013-03-05 11:02 -0500
Re: Recursive function Ana Dionísio <anadionisio257@gmail.com> - 2013-03-05 08:15 -0800
Re: Recursive function Ana Dionísio <anadionisio257@gmail.com> - 2013-03-05 08:15 -0800
Re: Recursive function Neil Cerutti <neilc@norwich.edu> - 2013-03-05 19:05 +0000
Re: Recursive function Vlastimil Brom <vlastimil.brom@gmail.com> - 2013-03-05 17:06 +0100
csiph-web