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Re: Question on for loop

Newsgroups comp.lang.python
Date 2013-03-05 03:12 -0800
References <d5f0feb6-533a-445b-a89a-8113c1668e9d@googlegroups.com> <7345f1f5-d958-4fef-ad50-81fb526b4f2f@googlegroups.com> <mailman.2848.1362415074.2939.python-list@python.org>
Subject Re: Question on for loop
From Bryan Devaney <bryan.devaney@gmail.com>
Message-ID <mailman.2877.1362481970.2939.python-list@python.org> (permalink)

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On Monday, March 4, 2013 4:37:11 PM UTC, Ian wrote:
> On Mon, Mar 4, 2013 at 7:34 AM, Bryan Devaney <bryan.devaney@gmail.com> wrote:
> 
> >>         if character not in lettersGuessed:
> 
> >>
> 
> >>         return True
> 
> >>
> 
> >> return False
> 
> >
> 
> > assuming a function is being used to pass each letter of the letters guessed inside a loop itself that only continues checking if true is returned, then that could work.
> 
> >
> 
> > It is however more work than is needed.
> 
> >
> 
> > If you made secretword a list,you could just
> 
> >
> 
> > set(secretword)&set(lettersguessed)
> 
> >
> 
> > and check the result is equal to secretword.
> 
> 
> 
> Check the result is equal to set(secretword), I think you mean.
> 
> 
> 
> set(secretword).issubset(set(lettersguessed))
> 
> 
> 
> might be slightly more efficient, since it would not need to build and
> 
> return an intersection set.
> 
> 
> 
> One might also just do:
> 
> 
> 
> all(letter in lettersguessed for letter in secretword)
> 
> 
> 
> Which will be efficient if lettersguessed is already a set.

You are correct. sorry for the misleading answer, was digging through old shell scripts all day yesterday and brain was obviously not not the better for it.

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Thread

Question on for loop newtopython <roshen.sethna@gmail.com> - 2013-03-04 04:18 -0800
  Re: Question on for loop leo kirotawa <kirotawa@gmail.com> - 2013-03-04 09:59 -0300
  Re: Question on for loop Joel Goldstick <joel.goldstick@gmail.com> - 2013-03-04 08:04 -0500
  Re: Question on for loop Dave Angel <davea@davea.name> - 2013-03-04 08:36 -0500
  Re: Question on for loop Bryan Devaney <bryan.devaney@gmail.com> - 2013-03-04 06:34 -0800
    Re: Question on for loop Ian Kelly <ian.g.kelly@gmail.com> - 2013-03-04 09:37 -0700
      Re: Question on for loop Bryan Devaney <bryan.devaney@gmail.com> - 2013-03-05 03:12 -0800
      Re: Question on for loop Bryan Devaney <bryan.devaney@gmail.com> - 2013-03-05 03:12 -0800
  Re: Question on for loop Rick Johnson <rantingrickjohnson@gmail.com> - 2013-03-04 07:41 -0800
  Re: Question on for loop Ricardo Aráoz <ricaraoz@gmail.com> - 2013-03-04 10:21 -0300

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