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Re: Issue with continous incrementing of unbroken sequence for a entire working day

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Hi,
Yes, i think checking only date is sufficient . here is my code:

from datetime import date

def read_data_file():
    with open("workfile.txt", 'r') as f:
        for line in f.readlines():
            read_data = line.split(' ')
    return read_data

def write_data_file(data):
    fo = open("workfile.txt", "w")
    fo.write(str(data))
    fo.close()

def comput_date(read_date, now_time, read_serial):
    if read_date == now_time:
        read_serial = int(read_serial)
        return read_serial + 1
    else:
        read_serial = 1
        return read_serial

def process_sales_record():
    now_time = time.strftime("%d-%m-%y")
    readdata = read_data_file()
    if readdata:
        read_serial = readdata[0]
        read_date = readdata[1]
        copute_date = comput_date(read_date, now_time, read_serial)
    serial_number = copute_date
    print serial_number
    sales_recrod = {'record1':'product1',
'record2':'product2','record3':'product3'}
    for i in sales_recrod:
        print sales_recrod[i]
        serial_number += 1
    print serial_number
    data = str(serial_number) + ' ' + now_time
    writedata = write_data_file(data)
    print readdata

Can you give me suggestion how can i improve this code....


---------- Forwarded message ----------
From: MRAB <python@mrabarnett.plus.com>
To: python-list@python.org
Cc:
Date: Fri, 01 Mar 2013 14:09:43 +0000
Subject: Re: Issue with continous incrementing of unbroken sequence
for a entire working day
On 2013-03-01 09:42, Morten Engvoldsen wrote:

    Hi,
    Thanks.. :)
    so simply i can use time.strftime("%d%-m-%y  %H:%M")  , and then i can
    compare the date....

I think you're only interested in the date, not the time of day:

time.strftime("%d-%m-%y")

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Re: Issue with continous incrementing of unbroken sequence for a entire working day Morten Engvoldsen <mortenengv@gmail.com> - 2013-03-01 17:31 +0100

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