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Groups > comp.lang.python > #40254
| Date | 2013-03-01 14:09 +0000 |
|---|---|
| From | MRAB <python@mrabarnett.plus.com> |
| Subject | Re: Issue with continous incrementing of unbroken sequence for a entire working day |
| References | <CAJ2vgs6zZpHC_p=SuE7QWf7NDvokMjmE1N-aEN3a6n_DXi2=aQ@mail.gmail.com> <CAJ2vgs59t2fkV_T-Kdcb5Mzsr5Q8M8z4P6NwMOftg-Y5zVR8wA@mail.gmail.com> <CAJ2vgs6dawhdDuz7HseGQA+1GPcmY4U2esgYBQzpH2HMOsgfnA@mail.gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.2724.1362146984.2939.python-list@python.org> (permalink) |
On 2013-03-01 09:42, Morten Engvoldsen wrote:
> Hi,
> Thanks.. :)
> so simply i can use time.strftime("%d%-m-%y %H:%M") , and then i can
> compare the date....
>
I think you're only interested in the date, not the time of day:
time.strftime("%d-%m-%y")
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Re: Issue with continous incrementing of unbroken sequence for a entire working day MRAB <python@mrabarnett.plus.com> - 2013-03-01 14:09 +0000
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