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Groups > comp.lang.python > #28207
| From | Peter Otten <__peter__@web.de> |
|---|---|
| Subject | Re: how to get character hex number? |
| Date | 2012-09-01 08:37 +0200 |
| Organization | None |
| References | <CA+YdQ_66ap1tQCRibdkntGvHqE1sp+Nv_kK2iiKh50GoAa=K6Q@mail.gmail.com> <50417631.1080508@tim.thechases.com> <CA+YdQ_6s1dj_ewZR0wT-WAd1uCwR8dhDDusbnkot4p5DkgmE5w@mail.gmail.com> <50418609.8030902@tim.thechases.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.27.1346481430.27098.python-list@python.org> (permalink) |
Tim Chase wrote:
> On 08/31/12 22:41, contro opinion wrote:
>>>>>>> u"english".encode("utf-8")
>>>> 'english'
>>>>>>> u"english".encode("ascii")
>>>> 'english'
>>>>
>>>> how can i get 656e676c697368 in encode method?
>>>
>>> At least in 2.x, you can do:
>>>
>>> >>> u"english".encode("hex")
>>> '656e676c697368'
>>
>> how about in python3.0?
>
> Well, in 3.1.3 at least, using the u"..." notation dies on me with
> an invalid syntax. However, as Ian suggests, you can do
>
> my_str = "english"
> "".join("%02x" % c for c in my_str.encode("ascii"))
>
> or whatever other encoding you want instead of "ascii".
Another option:
>>> binascii.hexlify("english".encode()).decode()
'656e676c697368'
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Re: how to get character hex number? Peter Otten <__peter__@web.de> - 2012-09-01 08:37 +0200
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