Re: Issue with continous incrementing of unbroken sequence for a entire working day

References	<CAJ2vgs6zZpHC_p=SuE7QWf7NDvokMjmE1N-aEN3a6n_DXi2=aQ@mail.gmail.com> <CAJ2vgs6iQuqKLUZPKq8wm9=x4mj4gzF+94g=afRARuxsByVAHQ@mail.gmail.com> <CAJ2vgs4GECUwwJ+zwMn+BopS1MSDiC0y39dZeExj_TqE9ndBYA@mail.gmail.com>
Date	2013-03-01 08:50 +1100
Subject	Re: Issue with continous incrementing of unbroken sequence for a entire working day
From	Chris Angelico <rosuav@gmail.com>
Newsgroups	comp.lang.python
Message-ID	<mailman.2689.1362088243.2939.python-list@python.org> (permalink)

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On Fri, Mar 1, 2013 at 8:44 AM, Morten Engvoldsen <mortenengv@gmail.com> wrote:
> Hi,
> Thanks all for suggestion...
>
> I am using current date as current date local time. I think
> datetime.datetime will provide current local date and time, so
> hopefullt the function take care
> if the local clock is changed...

The worst that can happen is that the date changes and your serial
resets when it shouldn't. Can you cope with that? (Or just blame it on
the user and let them cope?) If so, it's easy.

ChrisA

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Re: Issue with continous incrementing of unbroken sequence for a entire working day Chris Angelico <rosuav@gmail.com> - 2013-03-01 08:50 +1100

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