Re: Not x.islower() has different output than x.isupper() in list output...

From	Christopher Reimer <christopher_reimer@icloud.com>
Newsgroups	comp.lang.python
Subject	Re: Not x.islower() has different output than x.isupper() in list output...
Date	2016-04-30 10:36 -0700
Message-ID	<mailman.266.1462037788.32212.python-list@python.org> (permalink)
References	(2 earlier) <57241097.7020801@icloud.com> <1461998604.3888861.594056577.710E696D@webmail.messagingengine.com> <5724E1CF.9060905@icloud.com> <1462036309.4005755.594329209.1106AF27@webmail.messagingengine.com> <5724ED13.9070606@icloud.com>

Show all headers | View raw

On 4/30/2016 10:11 AM, Stephen Hansen wrote:
> You're thinking of the whole "string", but you're operating on 
> single-character substrings, and when " ".islower() is run, its false. 
> Because the two-pronged test, a) if all cased characters are lowercase 
> and b) there is at least one cased character. b) is failing. Ergo, 
> you're getting the underscores.

I see where the problem lies in my thinking. I went looking for a single 
line solution for the whole string. If I had constructed a for loop and 
tried to reduce it to a single line, I *may* have understood the 
relationship between the different parts. Or maybe not. Blaming the 
documentation is a lot easier. ;)

Thank you,

Chris R.

Back to comp.lang.python | Previous | Next | Find similar | Unroll thread

Thread

Re: Not x.islower() has different output than x.isupper() in list output... Christopher Reimer <christopher_reimer@icloud.com> - 2016-04-30 10:36 -0700

csiph-web