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Groups > comp.lang.python > #26003
| Date | 2012-07-24 20:08 +0100 |
|---|---|
| From | MRAB <python@mrabarnett.plus.com> |
| Subject | Re: no data exclution and unique combination. |
| References | <864b0104-daa8-4ea5-8003-6cfaab19fdea@googlegroups.com> <500EEEB6.1050904@mrabarnett.plus.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.2548.1343156914.4697.python-list@python.org> (permalink) |
On 24/07/2012 19:51, MRAB wrote: > On 24/07/2012 19:27, giuseppe.amatulli@gmail.com wrote: >> Hi, >> would like to take eliminate a specific number in an array and its correspondent in an other array, and vice-versa. >> >> given >> >> a=np.array([1,2,4,4,5,4,1,4,1,1,2,4]) >> b=np.array([1,2,3,5,4,4,1,3,2,1,3,4]) >> >> no_data_a=1 >> no_data_b=2 >> >> a_clean=array([4,4,5,4,4,4]) >> b_clean=array([3,5,4,4,3,4]) >> >> after i need to calculate unique combination in pairs to count the observations >> and obtain >> (4,3,2) >> (4,5,1) >> (5,4,1) >> (4,4,2) >> >> For the fist task i did >> >> a_No_data_a = a[a != no_data_a] >> b_No_data_a = b[a != no_data_a] >> >> b_clean = b_No_data_a[b_No_data_a != no_data_b] >> a_clean = a_No_data_a[a_No_data_a != no_data_b] >> >> but the results are not really stable. >> > mask = (a != no_data_a) & (b != no_data_b) > a_clean = a[mask] > b_clean = b[mask] > >> For the second task >> The np.unique would solve the problem if it can be apply to a two arrays. >> I couldn't figure out how to do the second part in numpy, so: from collections import Counter counts = Counter(zip(a_clean, b_clean)) counts = [pair + (count,) for pair, count in counts.items()]
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no data exclution and unique combination. giuseppe.amatulli@gmail.com - 2012-07-24 11:27 -0700
Re: no data exclution and unique combination. MRAB <python@mrabarnett.plus.com> - 2012-07-24 19:51 +0100
Re: no data exclution and unique combination. MRAB <python@mrabarnett.plus.com> - 2012-07-24 20:08 +0100
Re: no data exclution and unique combination. Terry Reedy <tjreedy@udel.edu> - 2012-07-24 15:32 -0400
Re: no data exclution and unique combination. giuseppe.amatulli@gmail.com - 2012-08-09 13:06 -0700
Re: no data exclution and unique combination. Dave Angel <d@davea.name> - 2012-08-09 17:23 -0400
Re: no data exclution and unique combination. Terry Reedy <tjreedy@udel.edu> - 2012-08-09 17:33 -0400
Re: no data exclution and unique combination. Hans Mulder <hansmu@xs4all.nl> - 2012-08-10 10:47 +0200
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