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Re: How to access the document for __call__ from command line?

From Terry Reedy <tjreedy@udel.edu>
Subject Re: How to access the document for __call__ from command line?
Date 2012-10-18 22:59 -0400
References <CABrM6wmHbfB9=UTATEfx5zKaOO=yxp4UBHVVJDnJG4bdWLSqTA@mail.gmail.com>
Newsgroups comp.lang.python
Message-ID <mailman.2492.1350615581.27098.python-list@python.org> (permalink)

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On 10/18/2012 10:30 PM, Peng Yu wrote:
> Hi,
>
> reference.pdf from python document has the following description. It
> is not accessible from help() in the command line. Is there an
> alternative so that I can quickly access these class attributes or
> method names from the command line?
>
> object.__call__(self [, args... ])
> Called when the instance is “called” as a function; if this method is
> defined, x(arg1, arg2, ...) is a
> shorthand for x.__call__(arg1, arg2, ...).

 >>> help(object.__call__)
Help on method-wrapper object:

__call__ = class method-wrapper(object)
  |  Methods defined here:
  |
  |  __call__(...)
  |      x.__call__(...) <==> x(...)
  |
snip not very helpful stuff

For a user class with a __call__ method with a docstring

 >>> class C:
	def __call__(self, x):
		"return the difference between self and x"
		return self-x

 >>> help(C.__call__)
Help on function __call__ in module __main__:

__call__(self, x)
     return the difference between self and x

Similarly for builtin methods you actually need to know about

 >>> help(list.append)
Help on method_descriptor:

append(...)
     L.append(object) -> None -- append object to end



-- 
Terry Jan Reedy

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Re: How to access the document for __call__ from command line? Terry Reedy <tjreedy@udel.edu> - 2012-10-18 22:59 -0400

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