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Groups > comp.lang.python > #98658
| From | Tim Johnson <tim@akwebsoft.com> |
|---|---|
| Newsgroups | comp.lang.python |
| Subject | Re: Using subprocess to capture a progress line |
| Date | 2015-11-11 09:52 -0900 |
| Organization | AkWebsoft |
| Message-ID | <mailman.249.1447267942.16136.python-list@python.org> (permalink) |
| References | <20151110224756.GA1944@mail.akwebsoft.com> <CAMw+j7LZH44RnPXgP4XVDiv62uJ_iFmsEm17QpsmNBSDr=uvJw@mail.gmail.com> <20151111161657.GE1944@mail.akwebsoft.com> <CAMw+j7K2V3xQX-cncfgJgxf9CsODe-Y2hS_A6ZTy7m45P6MVcw@mail.gmail.com> |
* Chris Warrick <kwpolska@gmail.com> [151111 07:54]: > On 11 November 2015 at 17:16, Tim Johnson <tim@akwebsoft.com> wrote: > >> (2) [don’t do it] do you need to intercept the lines? If you don’t set > >> stderr= and stdout=, things will print just fine. > > Got to try that before using the module, just for edification. > > At which point your initial code sample will become: > ########### > p = subprocess.Popen(list(args)) > ########### > Yeah, 'list is redundant. Progress is now showing, but I forgot to say that I've lost the original intent, and that was to examine each line so that I could pull out the title. No matter. I'm on the way to make the youtube_dl module working. cheers -- Tim http://www.akwebsoft.com, http://www.tj49.com
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Re: Using subprocess to capture a progress line Tim Johnson <tim@akwebsoft.com> - 2015-11-11 09:52 -0900
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