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RE: Lambda question

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>>>>> f = lambda x, n, acc=[]: f(x[n:], n, acc+[(x[:n])]) if x else acc

> Packing tail recursion into one line is bad for both understanding and 
> refactoring. Use better names and a docstring gives
> 
> def group(seq, n):
>    'Yield from seq successive disjoint slices of length n plus the 
> remainder'
>    for i in range(0,len(seq), n):
>      yield seq[i:i+]
> 
> -- 
> Terry Jan Reedy

Thank you all very much for this incredible help!  The original code 
now makes sense, and I was thrilled to see better and more efficient 
ways of doing this.  Thanks for taking the time to share your 
thoughts as well as the excellent detail everyone shared…  I really 
appreciate it!

Jay

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RE: Lambda question <jyoung79@kc.rr.com> - 2011-06-06 13:42 +0000

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