Re: "normalizing" a value

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Date	Thu, 2 Jul 2015 10:05:42 -0500
Subject	Re: "normalizing" a value
From	Skip Montanaro <skip.montanaro@gmail.com>
To	bvdp <bob@mellowood.ca>
Cc	Python <python-list@python.org>
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This looks like a straightforward linear transformation issue to me
(like Fahrenheit to Celsius). Add 50 to all input values, giving you
values in the range 0 to 100. Then scale them into your 0 to 12 range
by multiplying them by 12/100:

>>> for n in range(-50, 50, 3):
...   print n, n + 50, (n + 50) * 12 / 100
...
-50 0 0.0
-47 3 0.36
-44 6 0.72
-41 9 1.08
-38 12 1.44
...
34 84 10.08
37 87 10.44
40 90 10.8
43 93 11.16
46 96 11.52
49 99 11.88

Did I misread your request in some way?

Skip

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Thread

"normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 17:12 -0700
  Re: "normalizing" a value MRAB <python@mrabarnett.plus.com> - 2015-07-02 01:30 +0100
  Re: "normalizing" a value Paul Rubin <no.email@nospam.invalid> - 2015-07-01 17:36 -0700
  Re: "normalizing" a value Denis McMahon <denismfmcmahon@gmail.com> - 2015-07-02 01:06 +0000
  Re: "normalizing" a value random832@fastmail.us - 2015-07-01 21:27 -0400
    Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 18:49 -0700
      Re: "normalizing" a value random832@fastmail.us - 2015-07-01 22:23 -0400
        Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 19:41 -0700
      Re: "normalizing" a value Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2015-07-01 23:36 -0400
        Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-02 10:03 -0700
  Re: "normalizing" a value Steven D'Aprano <steve@pearwood.info> - 2015-07-02 12:15 +1000
    Re: "normalizing" a value bvdp <bob@mellowood.ca> - 2015-07-01 19:42 -0700
  Re: "normalizing" a value Mark Lawrence <breamoreboy@yahoo.co.uk> - 2015-07-02 05:41 +0100
  Re: "normalizing" a value Skip Montanaro <skip.montanaro@gmail.com> - 2015-07-02 10:05 -0500

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