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Groups > comp.lang.python > #39667
| From | Mark Lawrence <breamoreboy@yahoo.co.uk> |
|---|---|
| Subject | Re: time as float since Jan 1, 0001? |
| Date | 2013-02-23 13:41 +0000 |
| References | <roy-41E67E.08290123022013@news.panix.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.2342.1361626870.2939.python-list@python.org> (permalink) |
On 23/02/2013 13:29, Roy Smith wrote: > I'm working with matplotlib.plot_date(), which represents time as > "floats starting at January 1st, year 0001". Is there any > straight-forward way to get that out of a datetime? > > datetime.toordinal() gives me the number of days since that epoch, but > as an integer. I figured it wouldn't be too hard to just do: > > t.toordinal() + t.time().total_seconds() > > except it turns out that only timedelta supports total_seconds(); time > doesn't! > > I suppose I could do: > > t.toordinal() + t.hour / 24.0 \ > + t.minute / 1440.0 \ > + t.second / 86400.0 > > but that's really ugly. Is there no cleaner way to do this conversion? > IIRC you needn't bother, matplotlib will do all the conversions for you. In the highly likely case that I'm wrong this should help http://matplotlib.org/api/dates_api.html#module-matplotlib.dates -- Cheers. Mark Lawrence
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time as float since Jan 1, 0001? Roy Smith <roy@panix.com> - 2013-02-23 08:29 -0500
Re: time as float since Jan 1, 0001? Mark Lawrence <breamoreboy@yahoo.co.uk> - 2013-02-23 13:41 +0000
Re: time as float since Jan 1, 0001? Roy Smith <roy@panix.com> - 2013-02-23 08:49 -0500
Re: time as float since Jan 1, 0001? Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2013-02-23 14:08 -0500
Re: time as float since Jan 1, 0001? Chris Angelico <rosuav@gmail.com> - 2013-02-24 00:45 +1100
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