Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]


Groups > comp.lang.python > #6647

Re: Best way to compute length of arbitrary dimension vector?

X-FeedAbuse http://nntpfeed.proxad.net/abuse.pl feeded by 88.191.16.109
Path csiph.com!x330-a1.tempe.blueboxinc.net!usenet.pasdenom.info!news.dougwise.org!nntpfeed.proxad.net!nospam.fr.eu.org!usenet-fr.net!de-l.enfer-du-nord.net!feeder2.enfer-du-nord.net!feeder.news-service.com!newsfeed.xs4all.nl!newsfeed6.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail
Return-Path <python-python-list@m.gmane.org>
X-Original-To python-list@python.org
Delivered-To python-list@mail.python.org
X-Spam-Status OK 0.002
X-Spam-Evidence '*H*': 1.00; '*S*': 0.00; '(at': 0.03; 'function,': 0.07; 'python': 0.08; 'compute': 0.09; 'googled': 0.09; 'received:80.91': 0.09; 'received:80.91.229': 0.09; 'received:80.91.229.12': 0.09; 'received:gmane.org': 0.09; 'received:list': 0.09; 'received:lo.gmane.org': 0.09; '>>>': 0.12; 'def': 0.12; ';-)': 0.14; 'wrote:': 0.14; 'jumping': 0.16; 'received:dip.t-dialin.net': 0.16; 'received:t-dialin.net': 0.16; 'math': 0.16; 'seems': 0.21; 'all:': 0.23; 'elegant': 0.23; 'least,': 0.23; 'says': 0.27; 'wondering': 0.28; 'subject:?': 0.29; 'import': 0.29; 'class': 0.29; 'bit': 0.30; 'least': 0.30; 'from:addr:web.de': 0.30; 'seem': 0.32; "can't": 0.32; 'apply': 0.32; 'header:X-Complaints-To:1': 0.32; 'to:addr:python-list': 0.33; 'too': 0.33; "i've": 0.33; 'however,': 0.34; 'there': 0.35; 'case': 0.37; 'received:org': 0.38; 'but': 0.38; 'subject:: ': 0.38; "i'd": 0.39; 'header:Mime-Version:1': 0.39; 'got': 0.39; 'to:addr:python.org': 0.39; 'really': 0.40; 'almost': 0.60; 'total': 0.61; 'subject': 0.62; 'skip:1 10': 0.63; 'here': 0.66; '5.0': 0.84; '0.0': 0.91; 'gabriel': 0.91; 'subject:Best': 0.91
X-Injected-Via-Gmane http://gmane.org/
To python-list@python.org
From Peter Otten <__peter__@web.de>
Subject Re: Best way to compute length of arbitrary dimension vector?
Date Mon, 30 May 2011 11:46:01 +0200
Organization None
References <43d7a46e-3f48-4c11-a66b-a47a3d6b9b9d@k16g2000yqm.googlegroups.com>
Mime-Version 1.0
Content-Type text/plain; charset="ISO-8859-1"
Content-Transfer-Encoding 7Bit
X-Gmane-NNTP-Posting-Host p5084a968.dip.t-dialin.net
X-BeenThere python-list@python.org
X-Mailman-Version 2.1.12
Precedence list
List-Id General discussion list for the Python programming language <python-list.python.org>
List-Unsubscribe <http://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe>
List-Archive <http://mail.python.org/pipermail/python-list>
List-Post <mailto:python-list@python.org>
List-Help <mailto:python-list-request@python.org?subject=help>
List-Subscribe <http://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe>
Newsgroups comp.lang.python
Message-ID <mailman.2258.1306749013.9059.python-list@python.org> (permalink)
Lines 38
NNTP-Posting-Host 82.94.164.166
X-Trace 1306749013 news.xs4all.nl 49177 [::ffff:82.94.164.166]:44722
X-Complaints-To abuse@xs4all.nl
Xref x330-a1.tempe.blueboxinc.net comp.lang.python:6647

Show key headers only | View raw


Gabriel wrote:

> Well, the subject says it almost all: I'd like to write a small Vector
> class for arbitrary-dimensional vectors.
> 
> I am wondering what would be the most efficient and/or most elegant
> way to compute the length of such a Vector?
> 
> Right now, I've got
> 
>   def length(self):											# x.length() = || x ||
>     total = 0.0
>     for k in range(len(self._coords)):
>       d = self._coords[k]
>       total += d*d
>     return sqrt(total)
> 
> However, that seems a bit awkward to me (at least in Python ;-) ).
> 
> I know there is the reduce() function, but I can't seem to find a way
> to apply that to the case here (at least, not without jumping through
> too many hoops).
> 
> I have also googled a bit, but found nothing really elegant.

>>> class Vector(object):
...     def __init__(self, *coords):
...             self._coords = coords
...     def __abs__(self):
...             return math.sqrt(sum(x*x for x in self._coords))
...
>>> import math
>>> abs(Vector(1,1))
1.4142135623730951
>>> abs(Vector(3,4))
5.0

Back to comp.lang.python | Previous | NextPrevious in thread | Next in thread | Find similar | Unroll thread


Thread

Best way to compute length of arbitrary dimension vector? Gabriel <snoopy.67.z@googlemail.com> - 2011-05-30 02:11 -0700
  Re: Best way to compute length of arbitrary dimension vector? Chris Rebert <clp2@rebertia.com> - 2011-05-30 02:24 -0700
  Re: Best way to compute length of arbitrary dimension vector? Peter Otten <__peter__@web.de> - 2011-05-30 11:46 +0200
    Re: Best way to compute length of arbitrary dimension vector? Gabriel <snoopy.67.z@googlemail.com> - 2011-05-30 06:38 -0700
      Re: Best way to compute length of arbitrary dimension vector? Ian Kelly <ian.g.kelly@gmail.com> - 2011-06-02 17:19 -0600
        Re: Best way to compute length of arbitrary dimension vector? Gabriel <snoopy.67.z@googlemail.com> - 2011-06-03 14:53 -0700
          Re: Best way to compute length of arbitrary dimension vector? Ian Kelly <ian.g.kelly@gmail.com> - 2011-06-03 16:17 -0600
          Re: Best way to compute length of arbitrary dimension vector? Robert Kern <robert.kern@gmail.com> - 2011-06-03 18:12 -0500
  Re: Best way to compute length of arbitrary dimension vector? "Gabriel Genellina" <gagsl-py2@yahoo.com.ar> - 2011-05-30 16:01 -0300
    Re: Best way to compute length of arbitrary dimension vector? Gabriel <snoopy.67.z@googlemail.com> - 2011-06-01 12:35 -0700

csiph-web