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| From | Peter Otten <__peter__@web.de> |
| Subject | Re: Sorting in reverse is not the same as sorting then reversing |
| Date | Fri, 05 Jun 2015 16:59:50 +0200 |
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Steven D'Aprano wrote: > Sorting in reverse does not give the same result as sorting then > reversing. > > It's easiest to see with a key function: > > > py> a = ['fox', 'dog', 'DOG', 'cat', 'ape'] > py> b = a[:] > py> a.sort(key=str.lower, reverse=True) > py> b.sort(key=str.lower) > py> b.reverse() > py> a > ['fox', 'dog', 'DOG', 'cat', 'ape'] > py> b > ['fox', 'DOG', 'dog', 'cat', 'ape'] > > > Sorting in reverse keeps the initial order of any equal elements > unchanged. Sorting, then reversing, reverses them. If there were no reverse flag you could reverse, then sort, then reverse again. > (Thanks to Tim Peters for the tip.)
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Sorting in reverse is not the same as sorting then reversing Steven D'Aprano <steve@pearwood.info> - 2015-06-06 00:07 +1000 Re: Sorting in reverse is not the same as sorting then reversing Stefan Behnel <stefan_ml@behnel.de> - 2015-06-05 16:50 +0200 Re: Sorting in reverse is not the same as sorting then reversing Peter Otten <__peter__@web.de> - 2015-06-05 16:59 +0200 Re: Sorting in reverse is not the same as sorting then reversing Skip Montanaro <skip.montanaro@gmail.com> - 2015-06-05 10:28 -0500
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