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Re: Obtaining a full path name from file

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Date Tue, 24 May 2011 18:13:20 +0200
From Jean-Michel Pichavant <jeanmichel@sequans.com>
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To RVince <rvince99@gmail.com>
Subject Re: Obtaining a full path name from file
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RVince wrote:
> Ha! You;re right -- but is there a way to get it without the filename
> appended at the end?
>
> On May 24, 11:52 am, Tim Golden <m...@timgolden.me.uk> wrote:
>   
>> On 24/05/2011 16:36, RVince wrote:
>>
>>     
>>> s = "C:\AciiCsv\Gravity_Test_data\A.csv"
>>> f = open(s,"r")
>>>       
>>> How do I obtain the full pathname given the File, f? (which should
>>> equal "C:\AciiCsv\Gravity_Test_data"). I've tried all sorts of stuff
>>> and am just not finding it. Any help greatly appreciated !
>>>       
>> You're going to kick yourself:
>>
>> f.name
>>
>> TJG
>>     
>
>   
path, fileName = os.path.split(os.path.abspath(f.name))

JM

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Thread

Obtaining a full path name from file RVince <rvince99@gmail.com> - 2011-05-24 08:36 -0700
  Re: Obtaining a full path name from file Tim Golden <mail@timgolden.me.uk> - 2011-05-24 16:52 +0100
    Re: Obtaining a full path name from file RVince <rvince99@gmail.com> - 2011-05-24 09:04 -0700
      Re: Obtaining a full path name from file Chris Angelico <rosuav@gmail.com> - 2011-05-25 02:08 +1000
      Re: Obtaining a full path name from file Tim Golden <mail@timgolden.me.uk> - 2011-05-24 17:10 +0100
      Re: Obtaining a full path name from file Jean-Michel Pichavant <jeanmichel@sequans.com> - 2011-05-24 18:13 +0200
    Re: Obtaining a full path name from file Mel <mwilson@the-wire.com> - 2011-05-24 12:04 -0400
  Re: Obtaining a full path name from file Ulrich Eckhardt <ulrich.eckhardt@dominolaser.com> - 2011-05-25 08:36 +0200
    Re: Obtaining a full path name from file Tim Golden <mail@timgolden.me.uk> - 2011-05-25 08:29 +0100
  Re: Obtaining a full path name from file Dave Angel <davea@ieee.org> - 2011-05-25 07:05 -0400

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