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Groups > comp.lang.python > #85967
| Date | 2015-02-20 08:07 -0500 |
|---|---|
| From | Dave Angel <davea@davea.name> |
| Subject | Re: What behavior would you expect? |
| References | (1 earlier) <CANy1k1gMgGnqNcgTwjcqfYH-QctZthv89uXcU8SV9Uk6Wji=4A@mail.gmail.com> <CAPTjJmpeYwsQ=XLu5WicVEnqMZpvKJueZRrM9WGafcEm1BFatg@mail.gmail.com> <CANy1k1j8ni7TtZPq_a2r8TUvY13rh0oY8xt-t6+9KPxwfAYEyw@mail.gmail.com> <CAPTjJmpq3t4qb+VD+uL6w+=_wf5v0BFThYFM+a8JAe2RDXpTYg@mail.gmail.com> <CANy1k1j+_boVW4EP=fijUKFVRctzD8EETm3kZ==eoezA=S=a6Q@mail.gmail.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.18919.1424437670.18130.python-list@python.org> (permalink) |
On 02/20/2015 12:51 AM, Jason Friedman wrote:
>>
>> I'd still advise using my_list.sort() rather than sorted(), as you
>> don't need to retain the original.
>>
>>
> Hmm.
>
> Trying to figure out what that looks like.
> If I understand correctly, list.sort() returns None.
> What would I return to the caller?
>
return_list = ....
return_list.sort(key=..., reverse = True)
return return_list
>
> Oops, guess I'm not really returning a list, I'm returning an iterator.
Now you'll be returning a list, I believe.
--
DaveA
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Re: What behavior would you expect? Dave Angel <davea@davea.name> - 2015-02-20 08:07 -0500
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