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Re: Comparing types

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On 2/17/2013 1:34 AM, Jason Friedman wrote:
> I want to tell whether an object is a regular expression pattern.
>
> Python 3.2.3 (default, Oct 19 2012, 20:10:41)
> [GCC 4.6.3] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
>>>> import re
>>>> s = "hello"
>>>> type(s)
> <class 'str'>
>>>> isinstance(s, str)
> True
>>>> my_pattern = re.compile(s)
>>>> type(my_pattern)
> <class '_sre.SRE_Pattern'>

The .__name__ attribute of the class is '_sre.SRE_Pattern'

>>>> isinstance(my_pattern, _sre.SRE_Pattern)
> Traceback (most recent call last):
>    File "<stdin>", line 1, in <module>
> NameError: name '_sre' is not defined

but the class is not bound to a (builtin) name, including not to 
_sre.SRE_Pattern



-- 
Terry Jan Reedy

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Re: Comparing types Terry Reedy <tjreedy@udel.edu> - 2013-02-17 04:42 -0500

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