Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]

Groups > comp.lang.python > #38985

Re: Python-list Digest, Vol 113, Issue 111

Show key headers only | View raw

[Multipart message — attachments visible in raw view] - view raw

Hi, I don't know if I should ask this on here, or in the tutor section, but
I heard that http://www.lighttable.com was an innovative IDE, so I was
wondering if it works for python since I'm learning python over time.....
Thanks!


On Fri, Feb 15, 2013 at 5:25 PM, <python-list-request@python.org> wrote:

> Send Python-list mailing list submissions to
>         python-list@python.org
>
> To subscribe or unsubscribe via the World Wide Web, visit
>         http://mail.python.org/mailman/listinfo/python-list
> or, via email, send a message with subject or body 'help' to
>         python-list-request@python.org
>
> You can reach the person managing the list at
>         python-list-owner@python.org
>
> When replying, please edit your Subject line so it is more specific
> than "Re: Contents of Python-list digest..."
>
> Today's Topics:
>
>    1. Re: Howto parse a string using a char in python (John Gordon)
>    2. Re: New User-Need-Help (John Gordon)
>    3. Re: Howto parse a string using a char in python (Tim Chase)
>    4. Re: Howto parse a string using a char in python (David Robinow)
>    5. Re: Howto parse a string using a char in python (Mark Lawrence)
>    6. Re: Howto parse a string using a char in python (Gary Chambers)
>    7. Re: New User-Need-Help (Joel Goldstick)
>    8. Re: New User-Need-Help (Deborah Piotrowski)
>
>
> ---------- Forwarded message ----------
> From: John Gordon <gordon@panix.com>
> To: python-list@python.org
> Cc:
> Date: Fri, 15 Feb 2013 23:11:52 +0000 (UTC)
> Subject: Re: Howto parse a string using a char in python
> In <511ebf0c$0$21334$9a6e19ea@unlimited.newshosting.com> "Steve Goodwin" <
> sgoodwin@cfl.rr.com> writes:
>
> > I am looking for the python2.7 function(s) to parse a string from a colon
> > character ":"
>
> > Sounds simple enough.
>
> > For example, a string like "123456:789".  I just need the "123456"
> > substring.(left of the :)
>
> > I have looked at regular expressions and string functions, so far no
> luck.
> > Custom function required?
>
> Use the split() string function.
>
> --
> John Gordon                   A is for Amy, who fell down the stairs
> gordon@panix.com              B is for Basil, assaulted by bears
>                                 -- Edward Gorey, "The Gashlycrumb Tinies"
>
>
>
>
> ---------- Forwarded message ----------
> From: John Gordon <gordon@panix.com>
> To: python-list@python.org
> Cc:
> Date: Fri, 15 Feb 2013 23:14:20 +0000 (UTC)
> Subject: Re: New User-Need-Help
> In <mailman.1855.1360969699.2939.python-list@python.org> Deborah
> Piotrowski <spiceninja4u@gmail.com> writes:
>
> > print "Game Over"
> > input("\n\nPress the Enter Key to Exit")
> > Syntax Error: Invalid Syntax
>
> You're probably using Python version 3, but the book was written for
> version 2.  The print statement is handled a bit differently in version 3.
>
> Change your print statement to look like this:
>
>     print("Game Over")
>
> --
> John Gordon                   A is for Amy, who fell down the stairs
> gordon@panix.com              B is for Basil, assaulted by bears
>                                 -- Edward Gorey, "The Gashlycrumb Tinies"
>
>
>
>
> ---------- Forwarded message ----------
> From: Tim Chase <python.list@tim.thechases.com>
> To: "Steve Goodwin" <sgoodwin@cfl.rr.com>
> Cc: python-list@python.org
> Date: Fri, 15 Feb 2013 17:16:26 -0600
> Subject: Re: Howto parse a string using a char in python
> On 2013-02-15 18:04, Steve Goodwin wrote:
> > Hi,
> >
> > I am looking for the python2.7 function(s) to parse a string from a
> > colon character ":"
> >
> > Sounds simple enough.
> >
> > For example, a string like "123456:789".  I just need the "123456"
> > substring.(left of the :)
> >
> > I have looked at regular expressions and string functions, so far
> > no luck. Custom function required?
>
> With just a single character, it sounds like you want something like
>
>   whole = "123456:789"
>   parts = whole.split(':') # or .split(':', 1)
>   interesting = parts[0]
>
> No custom function needed.
>
> -tkc
>
>
>
>
>
>
> ---------- Forwarded message ----------
> From: David Robinow <drobinow@gmail.com>
> To: Steve Goodwin <sgoodwin@cfl.rr.com>
> Cc: python-list@python.org
> Date: Fri, 15 Feb 2013 18:19:09 -0500
> Subject: Re: Howto parse a string using a char in python
> On Fri, Feb 15, 2013 at 6:04 PM, Steve Goodwin <sgoodwin@cfl.rr.com>
> wrote:
> > Hi,
> >
> > I am looking for the python2.7 function(s) to parse a string from a colon
> > character ":"
> >
> > Sounds simple enough.
> >
> > For example, a string like "123456:789".  I just need the "123456"
> > substring.(left of the :)
> "123456:789".split(":")[0]
>
>
>
> ---------- Forwarded message ----------
> From: Mark Lawrence <breamoreboy@yahoo.co.uk>
> To: python-list@python.org
> Cc:
> Date: Fri, 15 Feb 2013 23:20:06 +0000
> Subject: Re: Howto parse a string using a char in python
> On 15/02/2013 23:04, Steve Goodwin wrote:
>
>> Hi,
>>
>> I am looking for the python2.7 function(s) to parse a string from a colon
>> character ":"
>>
>> Sounds simple enough.
>>
>> For example, a string like "123456:789".  I just need the "123456"
>> substring.(left of the :)
>>
>> I have looked at regular expressions and string functions, so far no luck.
>> Custom function required?
>>
>> Thank you.
>>
>> - Spoog98
>>
>>
>>
> More likely a visit to the opticians :)  See http://docs.python.org/2/**
> library/stdtypes.html#string-**methods<http://docs.python.org/2/library/stdtypes.html#string-methods>for the find and index methods.
>
> --
> Cheers.
>
> Mark Lawrence
>
>
>
>
> ---------- Forwarded message ----------
> From: Gary Chambers <gwchamb@gwcmail.com>
> To: Steve Goodwin <sgoodwin@cfl.rr.com>
> Cc: python-list@python.org
> Date: Fri, 15 Feb 2013 18:13:21 -0500
> Subject: Re: Howto parse a string using a char in python
> Steve,
>
> > I am looking for the python2.7 function(s) to parse a string from a colon
> > character ":"
> >
> > Sounds simple enough.
> >
> > For example, a string like "123456:789".  I just need the "123456"
> > substring.(left of the :)
>
> How about:
>
> newstr = str[:str.find(':')]
>
> --
> GC
>
> ---------- Forwarded message ----------
> From: Joel Goldstick <joel.goldstick@gmail.com>
> To: Bob Brusa <bob.brusa@gmail.com>
> Cc: "python-list@python.org" <python-list@python.org>, Deborah Piotrowski
> <spiceninja4u@gmail.com>
> Date: Fri, 15 Feb 2013 18:21:03 -0500
> Subject: Re: New User-Need-Help
>
> Print needs parense in python 3
> On Feb 15, 2013 5:48 PM, "Bob Brusa" <bob.brusa@gmail.com> wrote:
>
>>
>>
>> Am Freitag, 15. Februar 2013 schrieb Joel Goldstick :
>>
>>>
>>>
>>>
>>> On Fri, Feb 15, 2013 at 4:45 PM, Deborah Piotrowski <
>>> spiceninja4u@gmail.com> wrote:
>>>
>>>> Hi,
>>>>
>>>>
>>>> I am very new to Python, I am using the e-book "Python Programming for
>>>> the Absolute Beginner" and am starting with a simple "Game Over" Program.
>>>>  This is the code:which is extremely simple!
>>>> print"Game Over" raw_input("\n\nPress Enter Key to exit")
>>>>
>>>
>>> welcome Nicholas
>>>
>>>
>>> One important thing about python is indentation is important.  You have
>>> presented your code in a way that can't be.  Can you actually copy your
>>> program and paste it into an email message.  Also, Windows, Linux, Mac?
>>>
>>>
>>>
>>>> That's it. It is supposed to bring up a window that says "Game Over"
>>>> and at the bottom say "Press enter Key to exit" and when you press the
>>>> enter key it is supposed to exit(big suprise).
>>>> But all it does is highlight "raw_input" and says "invalid syntax" Now,
>>>> if I just put "print "Game Over"" then it says Game Over UNDERNEATH the
>>>> code I just printed!
>>>> now I am following the book to the *pixel* and that is not what is
>>>> supposed to happen!
>>>> Please email me back as soon as you get this...(if you are not to
>>>> busy).
>>>>
>>>> Thanks,Nicholas
>>>>
>>>> --
>>>> http://mail.python.org/mailman/listinfo/python-list
>>>>
>>>>
>>>
>>>
>>> --
>>> Joel Goldstick
>>> http://joelgoldstick.com
>>>
>>
>> Nicholas,
>> Could it be that you use a more recent version ( e. g. 3.3) of python? I
>> found that raw_input is indeed no longer recognized. Use input instead and
>> your code will work - at least it did so with python 3.3 on my iPad.
>> Bob
>>
>>
>> --
>> Von Gmail Mobile gesendet
>>
>
>
> ---------- Forwarded message ----------
> From: Deborah Piotrowski <spiceninja4u@gmail.com>
> To: Joel Goldstick <joel.goldstick@gmail.com>
> Cc: "python-list@python.org" <python-list@python.org>
> Date: Fri, 15 Feb 2013 16:25:36 -0700
> Subject: Re: New User-Need-Help
> WAIT!! It works now, I just needed to save it in script.
> Thank you guys so much!!
> My best regards, Nicholas
>
> On Fri, Feb 15, 2013 at 4:21 PM, Joel Goldstick <joel.goldstick@gmail.com>wrote:
>
>> Print needs parense in python 3
>> On Feb 15, 2013 5:48 PM, "Bob Brusa" <bob.brusa@gmail.com> wrote:
>>
>>>
>>>
>>> Am Freitag, 15. Februar 2013 schrieb Joel Goldstick :
>>>
>>>>
>>>>
>>>>
>>>> On Fri, Feb 15, 2013 at 4:45 PM, Deborah Piotrowski <
>>>> spiceninja4u@gmail.com> wrote:
>>>>
>>>>> Hi,
>>>>>
>>>>>
>>>>> I am very new to Python, I am using the e-book "Python Programming for
>>>>> the Absolute Beginner" and am starting with a simple "Game Over" Program.
>>>>>  This is the code:which is extremely simple!
>>>>> print"Game Over" raw_input("\n\nPress Enter Key to exit")
>>>>>
>>>>
>>>> welcome Nicholas
>>>>
>>>>
>>>> One important thing about python is indentation is important.  You have
>>>> presented your code in a way that can't be.  Can you actually copy your
>>>> program and paste it into an email message.  Also, Windows, Linux, Mac?
>>>>
>>>>
>>>>
>>>>> That's it. It is supposed to bring up a window that says "Game Over"
>>>>> and at the bottom say "Press enter Key to exit" and when you press the
>>>>> enter key it is supposed to exit(big suprise).
>>>>> But all it does is highlight "raw_input" and says "invalid syntax"
>>>>> Now, if I just put "print "Game Over"" then it says Game Over UNDERNEATH
>>>>> the code I just printed!
>>>>> now I am following the book to the *pixel* and that is not what is
>>>>> supposed to happen!
>>>>> Please email me back as soon as you get this...(if you are not to
>>>>> busy).
>>>>>
>>>>> Thanks,Nicholas
>>>>>
>>>>> --
>>>>> http://mail.python.org/mailman/listinfo/python-list
>>>>>
>>>>>
>>>>
>>>>
>>>> --
>>>> Joel Goldstick
>>>> http://joelgoldstick.com
>>>>
>>>
>>> Nicholas,
>>> Could it be that you use a more recent version ( e. g. 3.3) of python? I
>>> found that raw_input is indeed no longer recognized. Use input instead and
>>> your code will work - at least it did so with python 3.3 on my iPad.
>>> Bob
>>>
>>>
>>> --
>>> Von Gmail Mobile gesendet
>>>
>>
>
>
> --
> Nicholas J. Piotrowski
>
> --
> http://mail.python.org/mailman/listinfo/python-list
>

Back to comp.lang.python | Previous | Next | Find similar | Unroll thread

Thread

Re: Python-list Digest, Vol 113, Issue 111 Claira <waveclaira@gmail.com> - 2013-02-15 21:17 -0600

csiph-web