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| Date | Sat, 24 Jan 2015 20:35:41 +0000 |
| From | MRAB <python@mrabarnett.plus.com> |
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| Subject | Re: Alternative to multi-line lambdas: Assign-anywhere def statements |
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Show key headers only | View raw
On 2015-01-24 19:55, Chris Angelico wrote:
> On Sun, Jan 25, 2015 at 5:56 AM, Ethan Furman <ethan@stoneleaf.us> wrote:
>> If the non-generic is what you're concerned about:
>>
>> # not tested
>> dispatch_table_a = {}
>> dispatch_table_b = {}
>> dispatch_table_c = {}
>>
>> class dispatch:
>> def __init__(self, dispatch_table):
>> self.dispatch = dispatch_table
>> def __call__(self, func):
>> self.dispatch[func.__name__] = func
>> return func
>>
>> @dispatch(dispatch_table_a)
>> def foo(...):
>> pass
>
> That's still only able to assign to a key of a dictionary, using the
> function name. There's no way to represent fully arbitrary assignment
> in Python - normally, you can assign to a name, an attribute, a
> subscripted item, etc. (Augmented assignment is a different beast
> altogether, and doesn't really make sense with functions.) There's no
> easy way to say "@stash(dispatch_table_a['asdf'])" and have that end
> up assigning to exactly that.
>
Here's a slight variation on the theme:
class DispatchTable(dict):
def __call__(self, name):
def setter(func):
self[name] = func
return func
return setter
command = DispatchTable()
@command("foo")
def _(*args):
print("You asked to foo.")
@command("bar")
def _(*args):
print("There's no wine in the bar.")
@command("asdf")
def _(*args):
print("Asdf! Asdf!")
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Re: Alternative to multi-line lambdas: Assign-anywhere def statements MRAB <python@mrabarnett.plus.com> - 2015-01-24 20:35 +0000
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