Groups | Search | Server Info | Keyboard shortcuts | Login | Register [http] [https] [nntp] [nntps]
Groups > comp.lang.python > #45495
| Path | csiph.com!usenet.pasdenom.info!gegeweb.org!usenet-fr.net!nerim.net!novso.com!newsfeed.xs4all.nl!newsfeed3.news.xs4all.nl!xs4all!post.news.xs4all.nl!not-for-mail |
|---|---|
| Return-Path | <rosuav@gmail.com> |
| X-Original-To | python-list@python.org |
| Delivered-To | python-list@mail.python.org |
| X-Spam-Status | OK 0.064 |
| X-Spam-Evidence | '*H*': 0.88; '*S*': 0.01; 'variables': 0.07; 'advance': 0.07; 'integers': 0.09; 'issue:': 0.09; 'item.': 0.09; 'thx': 0.09; 'python': 0.11; '1.5,': 0.16; '32,': 0.16; 'from:addr:rosuav': 0.16; 'from:name:chris angelico': 0.16; 'great!': 0.16; 'happily': 0.16; 'subject:Two': 0.16; 'there...': 0.16; 'folks': 0.16; 'sat,': 0.16; 'wrote:': 0.18; 'variable': 0.18; 'bit': 0.19; 'trying': 0.19; 'print': 0.22; 'certainly': 0.24; 'code:': 0.26; 'header:In-Reply-To:1': 0.27; "doesn't": 0.30; 'message-id:@mail.gmail.com': 0.30; 'work.': 0.31; 'wright': 0.31; 'maybe': 0.34; 'problem': 0.35; '(2)': 0.35; 'but': 0.35; 'received:google.com': 0.35; 'add': 0.35; 'to:addr:python-list': 0.38; 'pm,': 0.38; 'stock': 0.39; 'to:addr:python.org': 0.39; 'skip:p 20': 0.39; 'prices': 0.60; 'entire': 0.61; "you're": 0.61; 'you.': 0.62; "you'll": 0.62; 'term': 0.63; 'sum': 0.64; 'total': 0.65; 'here': 0.66; 'close': 0.67; 'subject': 0.69; 'obvious': 0.74; 'confusing': 0.84; 'prices:': 0.84; 'stock.': 0.84; 'sum.': 0.84; 'together,': 0.84; 'novice': 0.91; 'fun!': 0.93; 'hand,': 0.93; '2013': 0.98 |
| DKIM-Signature | v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20120113; h=mime-version:x-received:in-reply-to:references:date:message-id :subject:from:to:content-type; bh=jPI1T6kzi2cbwembUeA7z0U2qsYxOhMRMMoQwVzsQt4=; b=ibGu8eaueamr3u5fXCl1X6kwge56q7hzCRFLtXwGvRP5BNqNizf5/xPP8OT9dHGruh g6nbXUFvbKsGT2d9JWC/BO1D2kkJwLI1LemR5mVQ/Tfcx+1FHHoJKR8iJYHGiZB3aX9/ Qd86GBGg90yBCWnEaYUo3uP36q0DIe/T7LhbR/rkJcAwYQht+yq0AB+0j8n7K0MkuOBT oVX64ITiBKWasJeDRkuU4vw53A53ROcnPxJKwUvki7qrzIe2xNXVzVizytUquf78IEQG PIc762/Hpe6NxTFeqrWgH4pO/V9mVsKsGQmMM061sseQpTAsbwCXv9V0eW/g2mGqmz3F ky2A== |
| MIME-Version | 1.0 |
| X-Received | by 10.220.109.66 with SMTP id i2mr1552226vcp.51.1368853830860; Fri, 17 May 2013 22:10:30 -0700 (PDT) |
| In-Reply-To | <6012d69f-b65e-4d65-90c4-f04876853f5e@googlegroups.com> |
| References | <6012d69f-b65e-4d65-90c4-f04876853f5e@googlegroups.com> |
| Date | Sat, 18 May 2013 15:10:30 +1000 |
| Subject | Re: Two Dictionaries and a Sum! |
| From | Chris Angelico <rosuav@gmail.com> |
| To | python-list@python.org |
| Content-Type | text/plain; charset=ISO-8859-1 |
| X-BeenThere | python-list@python.org |
| X-Mailman-Version | 2.1.15 |
| Precedence | list |
| List-Id | General discussion list for the Python programming language <python-list.python.org> |
| List-Unsubscribe | <http://mail.python.org/mailman/options/python-list>, <mailto:python-list-request@python.org?subject=unsubscribe> |
| List-Archive | <http://mail.python.org/pipermail/python-list/> |
| List-Post | <mailto:python-list@python.org> |
| List-Help | <mailto:python-list-request@python.org?subject=help> |
| List-Subscribe | <http://mail.python.org/mailman/listinfo/python-list>, <mailto:python-list-request@python.org?subject=subscribe> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.1793.1368853832.3114.python-list@python.org> (permalink) |
| Lines | 53 |
| NNTP-Posting-Host | 2001:888:2000:d::a6 |
| X-Trace | 1368853832 news.xs4all.nl 15977 [2001:888:2000:d::a6]:57306 |
| X-Complaints-To | abuse@xs4all.nl |
| Xref | csiph.com comp.lang.python:45495 |
Show key headers only | View raw
On Sat, May 18, 2013 at 2:19 PM, Bradley Wright
<bradley.wright.biz@gmail.com> wrote:
> Confusing subject for a confusing problem (to a novice like me of course!)
> Thx for the help in advance folks
>
> I have (2) dictionaries:
>
> prices = {
> "banana": 4,
> "apple": 2,
> "orange": 1.5,
> "pear": 3
> }
>
> stock = {
> "banana": 6,
> "apple": 0,
> "orange": 32,
> "pear": 15
> }
>
> Here's my instructions:
>
> consider this as an inventory and calculate the sum (thats 4*6 = 24 bananas!)
Let me reword your problem a little, maybe it'll be a bit clearer.
You're trying to calculate the total value of all stock on hand, eg
for insurance purposes. That's not 24 bananas, that's $24 of bananas.
And the part you want now is to get the total value of your entire
stock. Great! You're very close to there...
> HERES MY CODE:
>
> for key in prices:
> print prices[key]*stock[key]
>
> ISSUE:
> I need to find a way to add all of those together...any pointers?
... you just need to accumulate a sum. Since this is almost certainly
homework, I won't give you the answer, but here are a few pointers:
* You'll need a single variable (I use the term sloppily, Python
doesn't actually have variables per se) which will collect the final
total.
* Inside your loop, you're currently printing out an int/float with
the value of the current item. Just add it onto your accumulator.
* Python will happily work with integers and floats together, so you
can just do what's obvious and it'll work.
See where that takes you. Have fun! :)
ChrisA
Back to comp.lang.python | Previous | Next — Previous in thread | Next in thread | Find similar | Unroll thread
Two Dictionaries and a Sum! Bradley Wright <bradley.wright.biz@gmail.com> - 2013-05-17 21:19 -0700 Re: Two Dictionaries and a Sum! Spacelee <fjctlzy@gmail.com> - 2013-05-18 12:30 +0800 Re: Two Dictionaries and a Sum! nanobio <hektorlg@gmail.com> - 2013-05-17 22:20 -0700 Re: Two Dictionaries and a Sum! nanobio <hektorlg@gmail.com> - 2013-05-17 22:22 -0700 Re: Two Dictionaries and a Sum! Chris Angelico <rosuav@gmail.com> - 2013-05-18 15:10 +1000 Re: Two Dictionaries and a Sum! Roy Smith <roy@panix.com> - 2013-05-18 09:22 -0400
csiph-web