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| From | Wolfgang Maier <wolfgang.maier@biologie.uni-freiburg.de> |
| Subject | Re: what would be the regular expression for null byte present in a string |
| Date | Wed, 14 Jan 2015 15:21:33 +0100 |
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On 01/13/2015 02:40 PM, Shambhu Rajak wrote: > I have a string that I get as an output of a command as: > > '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n' > > I want to fetch ‘*10232ae8944a*’ from the above string. > > I want to find a re pattern that could replace all the \x01..\x0z to be > replace by empty string ‘’, so that I can get the desired portion of string > > Can anyone help me with a working regex for it. > Sorry, no regex either, but depending on what exact behavior you need str.isprintable() or even str.isalnum() could be for you: e.g. s_in = '\x01\x00\x00\x00\x00\x00\x00\x00\x0c\x00\x00\x0010232ae8944a\x02\x00\x00\x00\x00\x00\x00\x00\n' s_out = ''.join(c for c in s_in if c.isprintable()) Wolfgang
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Re: what would be the regular expression for null byte present in a string Wolfgang Maier <wolfgang.maier@biologie.uni-freiburg.de> - 2015-01-14 15:21 +0100
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