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Re: Namespace puzzle, list comprehension fails within class definition

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On 01/12/2015 12:25 PM, John Ladasky wrote:
> d = {0:"a", 1:"b", 2:"c", 3:"d"}
> e = [d[x] for x in (0,2)]
> 
> class Foo:
>     f = {0:"a", 1:"b", 2:"c", 3:"d"}
>     print(f)
>     g = [f[x] for x in (0,2)]

In Foo 'f' is part of an unnamed namespace; the list comp 'g' has its own namespace, effectively making be a nonlocal;
class name lookup skips nonlocal namespaces.

Workaround:  use an actual for loop.

--
~Ethan~

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Namespace puzzle, list comprehension fails within class definition John Ladasky <john_ladasky@sbcglobal.net> - 2015-01-12 12:25 -0800
  Re: Namespace puzzle, list comprehension fails within class definition Ethan Furman <ethan@stoneleaf.us> - 2015-01-12 12:40 -0800
    Re: Namespace puzzle, list comprehension fails within class definition John Ladasky <john_ladasky@sbcglobal.net> - 2015-01-12 12:49 -0800
    Re: Namespace puzzle, list comprehension fails within class definition Steven D'Aprano <steve@pearwood.info> - 2015-01-13 04:49 +0000
      Re: Namespace puzzle, list comprehension fails within class definition Ethan Furman <ethan@stoneleaf.us> - 2015-01-12 22:00 -0800
  Re: Namespace puzzle, list comprehension fails within class definition John Ladasky <john_ladasky@sbcglobal.net> - 2015-01-12 12:43 -0800
  Re: Namespace puzzle, list comprehension fails within class definition Chris Angelico <rosuav@gmail.com> - 2015-01-13 07:51 +1100

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