Re: Python 3 regex?

References	<54B40C85.5000806@emerytelcom.com>
Date	2015-01-13 05:48 +1100
Subject	Re: Python 3 regex?
From	Chris Angelico <rosuav@gmail.com>
Newsgroups	comp.lang.python
Message-ID	<mailman.17634.1421088499.18130.python-list@python.org> (permalink)

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On Tue, Jan 13, 2015 at 5:03 AM, Jason Bailey <jbailey@emerytelcom.com> wrote:
> Unfortunately, I get no matches. From output on the command line, I can see
> that Python is adding extra backslashes to my re.compile string. I have
> added the raw 'r' in front of the strings to prevent it, but to no avail.
>

Regexes are notoriously hard to debug. Is there any particular reason
you _have_ to use one here? ISTM you could simplify it enormously by
just looking for the opening string:

shared_network = "My-Network-FECO"
network = filebody.split("\nshared-network "+shared_network+"
{",1)[1].split("\n}\n")[0]

Assuming your file is always correctly indented, and assuming you
don't have any other instances of that header string, you should be
fine.

ChrisA

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Re: Python 3 regex? Chris Angelico <rosuav@gmail.com> - 2015-01-13 05:48 +1100

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