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Groups > comp.lang.python > #8003

Re: opening a file

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On Sun, 19 Jun 2011 23:00:38 -0700, Tim Hanson <tjhanson@yahoo.com>
declaimed the following in gmane.comp.python.general:

> Using linux and Python 2.6, learning how to work with files from a Windows 
> oriented textbook:
> 
> This works:
> infile=open('/foo/bar/prog/py_modules/this_is_a_test','r')
> 
> This doesn't:
> infile=open('~/prog/py_modules/this_is_a_test','r')
> 
> Can't I work with files using Unix expressions?

	I'd suspect not -- if that "Unix expression" really means a SHELL
expression...

	The command shell is responsible for translating the ~ into whatever
it represents (home directory?).

	Inside a Python script, you'll need to use the os.environ module to
retrieve the environment variable that represents the same information,
and join them yourself.

infile = open(os.path.join(os.environ["HOME"], "prog/.../...test"), "r")
-- 
	Wulfraed                 Dennis Lee Bieber         AF6VN
        wlfraed@ix.netcom.com    HTTP://wlfraed.home.netcom.com/

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Re: opening a file Dennis Lee Bieber <wlfraed@ix.netcom.com> - 2011-06-19 23:24 -0700

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