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Re: question on string object handling in Python 2.7.8

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On Wed, Dec 24, 2014 at 4:22 AM, Steven D'Aprano <
steve+comp.lang.python@pearwood.info> wrote:
> What happens here is that you time a piece of code to:
>
> - Build a large list containing 100 million individual int objects. Each
int
> object has to be allocated at run time, as does the list. Each int object
> is about 12 bytes in size.

Note to the OP: since you're using Python 2 you would do better to loop
over an xrange object instead of a range. xrange produces an iterator over
the desired range without needing to construct a single list containing all
of them. They would all still need to be allocated, but not all at once,
and memory could be reused.

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Thread

question on string object handling in Python 2.7.8 Dave Tian <dave.jing.tian@gmail.com> - 2014-12-23 20:28 -0500
  Re: question on string object handling in Python 2.7.8 Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2014-12-24 22:22 +1100
    Re: question on string object handling in Python 2.7.8 Ian Kelly <ian.g.kelly@gmail.com> - 2014-12-24 09:39 -0700
  Re: question on string object handling in Python 2.7.8 Gregory Ewing <greg.ewing@canterbury.ac.nz> - 2014-12-25 17:23 +1300
  Re: question on string object handling in Python 2.7.8 Denis McMahon <denismfmcmahon@gmail.com> - 2014-12-25 16:34 +0000

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