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Re: how to generate a wsdl file for a web service in python

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Date Sun, 21 Dec 2014 14:31:03 +0200
From Burak Arslan <burak.arslan@arskom.com.tr>
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To brice DORA <road01@yahoo.fr>, python-list@python.org
Subject Re: how to generate a wsdl file for a web service in python
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On 12/19/14 12:45, brice DORA wrote:
> i have already my python file which contains all methods of my web service. so do you give a example or tell me how i can do it...

No, all you need is there in that example.

You need to decorate your functions using Spyne's @rpc, denote
input/output types using Spyne's type markers, wrap it inside a subclass
of Spyne's ServiceBase, pass the resulting service class to a Spyne
application setting your input/output protocols (you probably want Soap)
and pass that application to a transport of your choice (you probably
want WsgiApplication). If you need a Wsgi server, use CherryPy.

Bon courage,
Burak

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Thread

how to generate a wsdl file for a web service in python brice DORA <road01@yahoo.fr> - 2014-12-18 01:58 -0800
  Re: how to generate a wsdl file for a web service in python Burak Arslan <burak.arslan@arskom.com.tr> - 2014-12-18 13:38 +0200
    Re: how to generate a wsdl file for a web service in python brice DORA <road01@yahoo.fr> - 2014-12-19 02:45 -0800
      Re: how to generate a wsdl file for a web service in python Burak Arslan <burak.arslan@arskom.com.tr> - 2014-12-21 14:31 +0200
        Re: how to generate a wsdl file for a web service in python brice DORA <road01@yahoo.fr> - 2014-12-24 01:23 -0800

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