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Groups > comp.lang.python > #92055
| From | Peter Otten <__peter__@web.de> |
|---|---|
| Subject | Re: Regular Expression |
| Date | 2015-06-04 16:00 +0200 |
| Organization | None |
| References | <c85bc324-37fe-469e-b3b1-b1d4e51bf7d8@googlegroups.com> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.162.1433426457.13271.python-list@python.org> (permalink) |
Palpandi wrote:
> This is the case. To split "string2" from "string1_string2" I am using
> re.split('_', "string1_string2", 1)[1].
>
> It is working fine for string "string1_string2" and output as "string2".
> But actually the problem is that if a sting is "__string1_string2" and the
> output is "_string1_string2". It is wrong.
>
> How to fix this issue?
Use str.rpartion():
>>> "one_two__three".rpartition("_")[-1]
'three'
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Regular Expression Palpandi <palpandi111@gmail.com> - 2015-06-04 06:36 -0700 Re: Regular Expression Larry Martell <larry.martell@gmail.com> - 2015-06-04 09:43 -0400 Re: Regular Expression Steven D'Aprano <steve@pearwood.info> - 2015-06-04 23:54 +1000 Re: Regular Expression Tim Chase <python.list@tim.thechases.com> - 2015-06-04 08:48 -0500 Re: Regular Expression Peter Otten <__peter__@web.de> - 2015-06-04 16:00 +0200 Re: Regular Expression Laura Creighton <lac@openend.se> - 2015-06-04 16:21 +0200
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