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Groups > comp.lang.python > #24445
| From | Terry Reedy <tjreedy@udel.edu> |
|---|---|
| Subject | Re: How can i call array_length to get the length of array object? |
| Date | 2012-06-25 16:20 -0400 |
| References | <1340524913.38366.YahooMailClassic@web164603.mail.gq1.yahoo.com> <1340525704.2880.YahooMailClassic@web164605.mail.gq1.yahoo.com> <mailman.1454.1340541869.4697.python-list@python.org> <87pq8orxzn.fsf@benfinney.id.au> <js9muq$iu9$1@dough.gmane.org> |
| Newsgroups | comp.lang.python |
| Message-ID | <mailman.1498.1340655907.4697.python-list@python.org> (permalink) |
On 6/25/2012 8:54 AM, Mark Lawrence wrote: > On 25/06/2012 02:17, Ben Finney wrote: >> Mark Lawrence<breamoreboy@yahoo.co.uk> writes: >> >>> On 24/06/2012 09:15, gmspro wrote: >>> >>>> Why __len__() where the original name if array_length? Why is method >>>> names like __NAME__ ? >> >> These are questions answered by getting a thorough grounding in the >> fundamentals of Python. Please follow the Python tutorial >> <URL:http://docs.python.org/tutorial/>, from beginning to end, to learn >> about the basics like this. >> >>> Why are you too bloody lazy to do any research before you post >>> questions? >> >> I understand your frustration in this case, but there's no call for such >> vitriol. Please keep it off this forum. >> > > From http://www.thefreedictionary.com/vitriol - "Bitterly abusive > feeling or expression." I do not believe that my comment above deserves > the term vitriol. I saw it more as sarcasm and an expression of frustration. -- Terry Jan Reedy
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Re: How can i call array_length to get the length of array object? Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-06-24 13:45 +0100
Re: How can i call array_length to get the length of array object? Ben Finney <ben+python@benfinney.id.au> - 2012-06-25 11:17 +1000
Re: How can i call array_length to get the length of array object? Mark Lawrence <breamoreboy@yahoo.co.uk> - 2012-06-25 13:54 +0100
Re: How can i call array_length to get the length of array object? Terry Reedy <tjreedy@udel.edu> - 2012-06-25 16:20 -0400
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