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Groups > comp.lang.python > #102963

Re: repr( open('/etc/motd', 'rt').read() )

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On Mon, Feb 15, 2016, at 08:05, Veek. M wrote:
> What is happening with # 1 # (repr)?
> repr calls __repr__ which gives you bytes.. why does this result in \\n

When you call a function that returns a string directly in the
interpreter prompt (i.e. without print), it passes the result to repr,
which means in this case repr has been called twice.

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repr( open('/etc/motd', 'rt').read() ) "Veek. M" <vek.m1234@gmail.com> - 2016-02-15 18:35 +0530
  Re: repr( open('/etc/motd', 'rt').read() ) Random832 <random832@fastmail.com> - 2016-02-15 09:47 -0500
  Re: repr( open('/etc/motd', 'rt').read() ) Terry Reedy <tjreedy@udel.edu> - 2016-02-15 15:03 -0500
  Re: repr( open('/etc/motd', 'rt').read() ) Steven D'Aprano <steve+comp.lang.python@pearwood.info> - 2016-02-16 17:43 +1100

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